Python 中的 SymPy | subset . next _ dictionary()

原文:https://www . geesforgeks . org/sympy-subset-next _ 词典编纂-in-python/

subset . next _ dictionary():next _ dictionary()是一个 sympy Python 库函数，返回下一个字典序子集。

语法: sympy . combinations . subset . subset . next _ 词典学()

返回: 下一个字典序子集

代码# 1:next _ 词典()示例

# Python code explaining
# SymPy.Subset.next_lexicographic()

# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset

# Using from 
# sympy.combinatorics.subset.Subsets.next_lexicographic()

# Creating Subset
a = Subset(['c', 'd'], ['geek', 'for', 'c', 'd'])

# next_lexicographic value
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)

输出:

子集 a next _ 词典顺序:['d']

代码# 2:next _ 词典()示例

# Python code explaining
# SymPy.Subset.next_lexicographic()

# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset

# Using from 
# sympy.combinatorics.subset.Subsets.next_lexicographic()

# Creating Subset
a = Subset(['k', 'a'], ['23', 'k', 'a'])

# next_lexicographic value
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)

输出:

子集 a next _ 词典顺序:['a']

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