Python 中的 SymPy | arrangement . next _ lex()

原文:https://www . geesforgeks . org/sympy-置换-next_lex-in-python/

arrangement . next _ lex():next _ lex()是一个 sympy Python 库函数，它返回字典顺序中的下一个排列，如果 self 是字典顺序中的最后一个排列，则返回 None。

语法:sympy . combinations .排列.置换. next_lex()

返回:字典顺序中的下一个排列

代码#1 : next_lex()示例

# Python code explaining
# SymPy.Permutation.next_lex()

# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation

# Using from sympy.combinatorics.permutations.Permutation.next_lex() method 

# creating Permutation
a = Permutation([[2, 0], [3, 1]])

b = Permutation([1, 3, 5, 4, 2, 0])

print ("Permutation a - next_lex form : ", a.next_lex())
print ("Permutation b - next_lex form : ", b.next_lex())

输出:

排列 a–next _ lex 形式:(0 2 1 3) 排列 b–next _ lex 形式:(5)(0 1 4 3 2)

代码#2 : next_lex()示例–2D 置换

# Python code explaining
# SymPy.Permutation.next_lex()

# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation

# Using from sympy.combinatorics.permutations.Permutation.next_lex() method 

# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])

print ("Permutation a - next_lex form : ", a.next_lex())

输出:

排列 a–next _ lex 形式:(6)(0 3 5)(1 2 4)

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