一个字符串中连续的有序数字
给定一个只包含数字的字符串，我们需要检查该字符串是否包含以递增顺序连续排列的数字。 注意:负数不算这个问题的一部分。所以我们认为输入只包含正整数。 示例:
Input : str = "1234"
Output : Yes
1
Explanation :
There are 1, 2, 3, 4 which are
consecutive and in increasing order.
And the starting number is 1
Input : str = "91012"
Output : No
Explanation :
There are no such sequence in the
string.
Input : str = "99100"
Output : Yes
99
Explanation : The consecutive sequential
numbers are 99, 100
Input : str = "010203"
Output : NO
Explanation :
Although at first glance there seems to
be 01, 02, 03\. But those wouldn't be
considered a number. 01 is not 1 it's 0, 1
方法:一个容易实现且有用的方法是首先开始取一个字符(假设我们的字符串以 1 位数开头)，然后通过串联下一个数字形成一个新的字符串，直到新字符串的长度等于原始字符串。 也许一个例子可以澄清: 我们来举个例子【99100】
C++
// CPP Program to check whether a string contains
// consecutive sequential numbers or not
#include <iostream>
using namespace std;
// function to check consecutive sequential number
int isConsecutive(string str)
{
// variable to store starting number
int start;
// length of the input string
int length = str.size();
// find the number till half of the string
for (int i = 0; i < length / 2; i++) {
// new string containing the starting
// substring of input string
string new_str = str.substr(0, i + 1);
// converting starting substring into number
int num = atoi(new_str.c_str());
// backing up the starting number in start
start = num;
// while loop until the new_string is
// smaller than input string
while (new_str.size() < length) {
// next number
num++;
// concatenate the next number
new_str = new_str + to_string(num);
}
// check if new string becomes equal to
// input string
if (new_str == str)
return start;
}
// if string doesn't contains consecutive numbers
return -1;
}
// Driver's Code
int main()
{
string str = "99100";
cout << "String: " << str << endl;
int start = isConsecutive(str);
if (start != -1)
cout << "Yes \n" << start << endl;
else
cout << "No" << endl;
string str1 = "121315";
cout << "\nString: " << str1 << endl;
start = isConsecutive(str1);
if (start != -1)
cout << "Yes \n" << start << endl;
else
cout << "No" << endl;
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java Program to check whether a String contains
// consecutive sequential numbers or not
class GFG
{
// function to check consecutive sequential number
static int isConsecutive(String str)
{
// variable to store starting number
int start;
// length of the input String
int length = str.length();
// find the number till half of the String
for (int i = 0; i < length / 2; i++)
{
// new String containing the starting
// substring of input String
String new_str = str.substring(0, i + 1);
// converting starting substring into number
int num = Integer.parseInt(new_str);
// backing up the starting number in start
start = num;
// while loop until the new_String is
// smaller than input String
while (new_str.length() < length)
{
// next number
num++;
// concatenate the next number
new_str = new_str + String.valueOf(num);
}
// check if new String becomes equal to
// input String
if (new_str.equals(str))
return start;
}
// if String doesn't contains consecutive numbers
return -1;
}
// Driver Code
public static void main(String[] args)
{
String str = "99100";
System.out.println("String: " + str);
int start = isConsecutive(str);
if (start != -1)
System.out.println("Yes \n" + start);
else
System.out.println("No");
String str1 = "121315";
System.out.println("\nString: " + str1);
start = isConsecutive(str1);
if (start != -1)
System.out.println("Yes \n" + start);
else
System.out.println("No");
}
}
// This code contributed by Rajput-Ji
C
// C# Program to check whether a String contains
// consecutive sequential numbers or not
using System;
class GFG
{
// function to check consecutive sequential number
static int isConsecutive(String str)
{
// variable to store starting number
int start;
// length of the input String
int length = str.Length;
// find the number till half of the String
for (int i = 0; i < length / 2; i++)
{
// new String containing the starting
// substring of input String
String new_str = str.Substring(0, i + 1);
// converting starting substring into number
int num = int.Parse(new_str);
// backing up the starting number in start
start = num;
// while loop until the new_String is
// smaller than input String
while (new_str.Length < length)
{
// next number
num++;
// concatenate the next number
new_str = new_str + String.Join("",num);
}
// check if new String becomes equal to
// input String
if (new_str.Equals(str))
return start;
}
// if String doesn't contains consecutive numbers
return -1;
}
// Driver Code
public static void Main(String[] args)
{
String str = "99100";
Console.WriteLine("String: " + str);
int start = isConsecutive(str);
if (start != -1)
Console.WriteLine("Yes \n" + start);
else
Console.WriteLine("No");
String str1 = "121315";
Console.WriteLine("\nString: " + str1);
start = isConsecutive(str1);
if (start != -1)
Console.WriteLine("Yes \n" + start);
else
Console.WriteLine("No");
}
}
// This code has been contributed by 29AjayKumar
java 描述语言
<script>
// JavaScript Program to check whether a String contains
// consecutive sequential numbers or not
// function to check consecutive sequential number
function isConsecutive(str)
{
// variable to store starting number
let start;
// length of the input String
let length = str.length;
// find the number till half of the String
for (let i = 0; i < length / 2; i++)
{
// new String containing the starting
// substring of input String
let new_str = str.substring(0, i + 1);
// converting starting substring into number
let num = parseInt(new_str);
// backing up the starting number in start
start = num;
// while loop until the new_String is
// smaller than input String
while (new_str.length < length)
{
// next number
num++;
// concatenate the next number
new_str = new_str + (num).toString();
}
// check if new String becomes equal to
// input String
if (new_str == (str))
return start;
}
// if String doesn't contains consecutive numbers
return -1;
}
// Driver Code
let str = "99100";
document.write("String: " + str+"<br>");
let start = isConsecutive(str);
if (start != -1)
document.write("Yes <br>" + start+"<br>");
else
document.write("No<br>");
let str1 = "121315";
document.write("<br>String: " + str1+"<br>");
start = isConsecutive(str1);
if (start != -1)
document.write("Yes <br>" + start+"<br>");
else
document.write("No<br>");
// This code is contributed by rag2127
</script>
Output:
String: 99100
Yes
99
String: 121315
No
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