检查给定的字符串是否可以分成四个不同的字符串
原文:https://www . geesforgeks . org/check-given-string-can-split-四个不同的字符串/
给定一个字符串，任务是检查我们是否可以将它分成 4 个字符串，这样每个字符串都不是空的，并且彼此不同。
示例:
Input : str[] = "geeksforgeeks"
Output : Yes
"geeks", "for", "gee", "ks" are four
distinct strings that can form from
given string.
Input : str[] = "aaabb"
Output : No
观察如果字符串的长度大于等于 10，那么每次都可以拆分成四部分。假设，长度是 10，那么长度为 1，2，3，4 的字符串可以被制作。 对于长度小于 10 的字符串，我们可以使用蛮力，即迭代所有可能的字符串分割方法，并检查每一种方法。
If length is more than 10
return true
Else (If length is less than 10)
Use Brute Force method to check
if we can break it in four distinct
strings.
以下是上述想法的实现。
C++
// C++ program to check if we can break a string
// into four distinct strings.
#include<bits/stdc++.h>
using namespace std;
// Return if the given string can be split or not.
bool check(string s)
{
// We can always break a string of size 10 or
// more into four distinct strings.
if (s.size() >= 10)
return true;
// Brute Force
for (int i =1; i < s.size(); i++)
{
for (int j = i + 1; j < s.size(); j++)
{
for (int k = j + 1; k < s.size(); k++)
{
// Making 4 string from the given string
string s1 = s.substr(0, i);
string s2 = s.substr(i, j - i);
string s3 = s.substr(j, k - j);
string s4 = s.substr(k, s.size() - k);
// Checking if they are distinct or not.
if (s1 != s2 && s1 != s3 && s1 != s4 &&
s2 != s3 && s2 != s4 && s3 != s4)
return true;
}
}
}
return false;
}
// Driven Program
int main()
{
string str = "aaabb";
(check(str))? (cout << "Yes" << endl):
(cout << "No" << endl);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to check if we can break a string
// into four distinct strings.
class GFG
{
// Return true if both strings are equal
public static boolean strcheck(String s1, String s2)
{
if (s1.compareTo(s2) != 0)
return false;
return true;
}
// Return if the given string can be split or not.
public static boolean check(String s)
{
if (s.length() >= 10)
return true;
// Brute Force
for (int i = 1; i < s.length(); i++)
{
for (int j = i + 1; j < s.length(); j++)
{
for (int k = j + 1; k < s.length(); k++)
{
// Making 4 string from the given string
String s1 = "", s2 = "", s3 = "", s4 = "";
try
{
s1 = s.substring(0, i);
s2 = s.substring(i, j - i);
s3 = s.substring(j, k - j);
s4 = s.substring(k, s.length() - k);
}
catch (StringIndexOutOfBoundsException e) {
}
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
// Driver code
public static void main(String[] args)
{
String str = "aaabb";
if (check(str))
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed by
// sanjeev2552
Python 3
# Python3 program to check if we can
# break a into four distinct strings.
# Return if the given string can be
# split or not.
def check(s):
# We can always break a of size 10 or
# more into four distinct strings.
if (len(s) >= 10):
return True
# Brute Force
for i in range(1, len(s)):
for j in range(i + 1, len(s)):
for k in range(j + 1, len(s)):
# Making 4 from the given
s1 = s[0:i]
s2 = s[i:j - i]
s3 = s[j: k - j]
s4 = s[k: len(s) - k]
# Checking if they are distinct or not.
if (s1 != s2 and s1 != s3 and s1 != s4 and
s2 != s3 and s2 != s4 and s3 != s4):
return True
return False
# Driver Code
if __name__ == '__main__':
str = "aaabb"
print("Yes") if(check(str)) else print("NO")
# This code is contributed
# by SHUBHAMSINGH10
C
// C# program to check if we can break a string
// into four distinct strings.
using System;
class GFG
{
// Return true if both strings are equal
public static Boolean strcheck(String s1,
String s2)
{
if (s1.CompareTo(s2) != 0)
return false;
return true;
}
// Return if the given string
// can be split or not.
public static Boolean check(String s)
{
if (s.Length >= 10)
return true;
// Brute Force
for (int i = 1; i < s.Length; i++)
{
for (int j = i + 1; j < s.Length; j++)
{
for (int k = j + 1; k < s.Length; k++)
{
// Making 4 string from the given string
String s1 = "", s2 = "",
s3 = "", s4 = "";
try
{
s1 = s.Substring(0, i);
s2 = s.Substring(i, j - i);
s3 = s.Substring(j, k - j);
s4 = s.Substring(k, s.Length - k);
}
catch (Exception e) {
}
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
// Driver code
public static void Main(String[] args)
{
String str = "aaabb";
if (check(str))
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed by Princi Singh
java 描述语言
<script>
// JavaScript program to check if we can break a string
// into four distinct strings.
// Return true if both strings are equal
function strcheck(s1, s2)
{
if (s1.localeCompare(s2) != 0)
return false;
return true;
}
// Return if the given string can be split or not.
function check(s)
{
if (s.length >= 10)
return true;
// Brute Force
for (let i = 1; i < s.length; i++)
{
for (let j = i + 1; j < s.length; j++)
{
for (let k = j + 1; k < s.length; k++)
{
// Making 4 string from the given string
let s1 = "", s2 = "", s3 = "", s4 = "";
s1 = s.substring(0, i);
s2 = s.substring(i, i + j - i);
s3 = s.substring(j, j + k - j);
s4 = s.substring(k, k + s.length - k);
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
let str = "aaabb";
if (check(str))
document.write("Yes");
else
document.write("No");
</script>
输出:
No
本文由 Anuj Chauhan 供稿。如果你喜欢 GeeksforGeeks 并想投稿，你也可以使用write.geeksforgeeks.org写一篇文章或者把你的文章邮寄到 review-team@geeksforgeeks.org。看到你的文章出现在极客博客主页上，帮助其他极客。 如果你发现任何不正确的地方，或者你想分享更多关于上面讨论的话题的信息，请写评论。
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