惊人的数字
惊人数是一个数 N ，其表示可以分解为两部分， a 和 b ，使得 N 等于从 a 到 b 和 a + b = N 的整数之和，其中'+表示串联。 很少有惊人的数字是:
15, 27, 429, 1353, 1863, 3388, 3591, 7119..
检查 N 是否是一个惊人的数字
给定一个数字 N ，任务是检查 N 是否是一个惊人的数字。如果 N 是一个惊人的数字，那么打印“是”否则打印“否”。 示例:
输入:N = 429 T3】输出:是 T6】说明:T8】429 = 4+5+6……..+ 29，其中 a = 4、 b = 29 、 a + b = 429 其中+表示串联 输入: N = 28 输出:否
方法:想法是运行 I 和 j 的两个循环，找到从 I 到和变成> = N 的所有整数的和。如果在任何时间点和变成等于 N，那么我们也将检查 I 和 j 的连接是否等于 N。如果等于，那么这个数字就是一个惊人的数字 下面是上面方法的实现:
C++
// C++ implementation for the
// above approach
#include <bits/stdc++.h>
using namespace std;
// Function to concatenate
// two integers into one
int concat(int a, int b)
{
// Convert both the integers to string
string s1 = to_string(a);
string s2 = to_string(b);
// Concatenate both strings
string s = s1 + s2;
// Convert the concatenated string
// to integer
int c = stoi(s);
// return the formed integer
return c;
}
// Function to check if N is a
// Astonishing number
bool isAstonishing(int n)
{
// Loop to find sum of all integers
// from i till the sum becomes >= n
for (int i = 1; i < n; i++) {
// variable to store
// sum of all integers
// from i to j and
// check if sum and
// concatenation equals n or not
int sum = 0;
for (int j = i; j < n; j++) {
sum += j;
if (sum == n) {
// finding concatenation
// of i and j
int concatenation
= concat(i, j);
// condition for
// Astonishing number
if (concatenation == n) {
return true;
}
}
}
}
return false;
}
// Driver Code
int main()
{
// Given Number
int n = 429;
// Function Call
if (isAstonishing(n))
cout << "Yes";
else
cout << "No";
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java implementation for the
// above approach
import java.io.*;
class GFG{
// Function to concatenate
// two integers into one
static int concat(int a, int b)
{
// Convert both the integers to String
String s1 = Integer.toString(a);
String s2 = Integer.toString(b);
// Concatenate both Strings
String s = s1 + s2;
// Convert the concatenated String
// to integer
int c = Integer.parseInt(s);
// return the formed integer
return c;
}
// Function to check if N is a
// Astonishing number
static boolean isAstonishing(int n)
{
// Loop to find sum of all integers
// from i till the sum becomes >= n
for (int i = 1; i < n; i++)
{
// variable to store
// sum of all integers
// from i to j and
// check if sum and
// concatenation equals n or not
int sum = 0;
for (int j = i; j < n; j++)
{
sum += j;
if (sum == n)
{
// finding concatenation
// of i and j
int concatenation = concat(i, j);
// condition for
// Astonishing number
if (concatenation == n)
{
return true;
}
}
}
}
return false;
}
// Driver Code
public static void main (String[] args)
{
// Given Number
int n = 429;
// Function Call
if (isAstonishing(n))
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed by shubhamsingh10
Python 3
# Python3 implementation for the
# above approach
# Function to concatenate
# two integers into one
def concat(a, b):
# Convert both the integers to string
s1 = str(a)
s2 = str(b)
# Concatenate both strings
s = s1 + s2
# Convert the concatenated string
# to integer
c = int(s)
# return the formed integer
return c
# Function to check if N is a
# Astonishing number
def isAstonishing(n):
# Loop to find sum of all integers
# from i till the sum becomes >= n
for i in range(n):
# variable to store
# sum of all integers
# from i to j and
# check if sum and
# concatenation equals n or not
sum = 0
for j in range(i, n):
sum += j
if (sum == n):
# finding concatenation
# of i and j
concatenation = concat(i, j)
# condition for
# Astonishing number
if (concatenation == n):
return True
return False
# Driver Code
# Given Number
n = 429
# Function Call
if (isAstonishing(n)):
print('Yes')
else:
print('No')
# This code is contributed by Yatin
C
// C# implementation for the
// above approach
using System;
class GFG{
// Function to concatenate
// two integers into one
static int concat(int a, int b)
{
// Convert both the integers to String
String s1 = a.ToString();
String s2 = b.ToString();
// Concatenate both Strings
String s = s1 + s2;
// Convert the concatenated String
// to integer
int c = Int32.Parse(s);
// return the formed integer
return c;
}
// Function to check if N is a
// Astonishing number
static bool isAstonishing(int n)
{
// Loop to find sum of all integers
// from i till the sum becomes >= n
for (int i = 1; i < n; i++)
{
// variable to store
// sum of all integers
// from i to j and
// check if sum and
// concatenation equals n or not
int sum = 0;
for (int j = i; j < n; j++)
{
sum += j;
if (sum == n)
{
// finding concatenation
// of i and j
int concatenation = concat(i, j);
// condition for
// Astonishing number
if (concatenation == n)
{
return true;
}
}
}
}
return false;
}
// Driver Code
public static void Main(String[] args)
{
// Given Number
int n = 429;
// Function Call
if (isAstonishing(n))
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed by 29AjayKumar
java 描述语言
<script>
// Javascript implementation for the
// above approach
// Function to concatenate
// two integers into one
function concat(a, b)
{
// Convert both the integers to string
var s1 = a.toString();
var s2 = b.toString();
// Concatenate both strings
var s = s1 + s2;
// Convert the concatenated string
// to integer
var c = s;
// return the formed integer
return c;
}
// Function to check if N is a
// Astonishing number
function isAstonishing(n)
{
// Loop to find sum of all integers
// from i till the sum becomes >= n
for (var i = 1; i < n; i++) {
// variable to store
// sum of all integers
// from i to j and
// check if sum and
// concatenation equals n or not
var sum = 0;
for (var j = i; j < n; j++) {
sum += j;
if (sum == n) {
// finding concatenation
// of i and j
var concatenation
= concat(i, j);
// condition for
// Astonishing number
if (concatenation == n) {
return true;
}
}
}
}
return false;
}
// Driver Code
// Given Number
var n = 429;
// Function Call
if (isAstonishing(n))
document.write( "Yes");
else
document.write( "No");
</script>
Output:
Yes
时间复杂度: O(n)
辅助空间: O(1)
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