Java 中的 Java.lang.StrictMath 类|第 2 集
原文:https://www . geesforgeks . org/Java-lang-strict math-class-Java-set-2/
Java 中的 Java.lang.StrictMath 类|集 1 Java . lang . strict math 类的更多方法
13。exp():Java . lang . strict math . exp(double arg)方法返回欧拉数的双参数幂。
重要病例:
- 结果是 NaN,如果参数是 NaN。
- 如果参数为+ve 无穷大,则结果为+ve 无穷大。
- 如果参数为-ve 无穷大,则结果为+ve 零。
语法:
public static double exp(double arg)
Parameters:
arg - argument passed.
Returns:
Euler’s number raised to the power of passed argument
14。cosh():Java . lang . strict math . cosh()方法返回传递的参数的双曲余弦值。
特殊情况:
- 结果是 NaN,如果参数是 NaN。
- 如果参数为零,则结果为 1.0。
- 如果参数为无穷大,则结果为+ve 无穷大。
语法:
public static double cosh(double arg)
Parameters:
arg - The number whose hyperbolic cosine is to be returned.
Returns:
the hyperbolic cosine of the argument arg.
15。递减精确():java.lang.StrictMath .减量精确()方法将传递的参数值递减 1。
语法:
public static int decrementExact(int arg)
or
public static long decrementExact(long arg)
Parameters:
arg - argument passed.
Returns:
return argument decremented by one.
Throws:
Exception if the result overflows long or int datatype, according to the
argumented data type.
Java 代码,解释 lang 中的 exp()、减量 Exact()、cosh()方法。StrictMath 类。
Java 语言(一种计算机语言,尤用于创建网站)
// Java program explaining lang.StrictMath class methods
// exp(), decrementExact(), cosh()
import java.math.*;
public class NewClass
{
public static void main(String[] args)
{
// Use of cosh() method
double value = 2;
double coshValue = StrictMath.cosh(value);
System.out.println("Hyperbolic Cosine of " + coshValue);
System.out.println("");
// Use of decrementExact() method
int result = StrictMath.decrementExact(3051);
System.out.println("Use of decrementExact() : " + result);
System.out.println("");
// Use of exp() method
// declare the exponent to be used
double exponent = 34;
// raise e to exponent declared
double expVal = StrictMath.exp(exponent);
System.out.println("Value of exp : "+ expVal);
}
}
输出:
Using addExact() : 9
acos value of Asini : NaN
acos value of Asinj : 0.054858647341251204
cube root : 6.0
16。log 10():Java . lang . strict math . log 10()方法返回传递的参数的 base10 对数值。
Syntax:
public static double log(double arg)
Parameters:
arg - argument passed.
Returns:
base10 logarithmic value of the argument passed.
17。pow():Java . lang . strict math . pow(double b,double e) 方法返回值为beT5】
Syntax:
public static double pow(double b, double e)
Parameters:
b : base
e : exponent
Returns:
value as base<sup>exponent</sup>
18。incrementExact():Java . lang . strict math . incrementExact()方法通过增加参数的值来返回参数。
Syntax:
public static int incrementExact(int arg)
or
public static long incrementExact(long arg)
Parameters:
arg - the argument
Returns:
incremented value of the argument
JAVA 代码,用 lang 解释 incrementExact(),log10(),pow()方法。StrictMath 类。
Java 语言(一种计算机语言,尤用于创建网站)
// Java program explaining lang.MATH class methods
// incrementExact(), log10(), pow()
import java.lang.*;
public class NewClass
{
public static void main(String[] args)
{
// Use of incrementExact() method
int f1 = 30, f2 = -56;
f1 = StrictMath.incrementExact(f1);
System.out.println("Incremented value of f1 : " + f1);
f2 = StrictMath.incrementExact(f2);
System.out.println("Incremented value of f2 : " + f2);
System.out.println("");
// Use of log10() method
double value = 10;
double logValue = StrictMath.log10(value);
System.out.println("Log10 value of 10 : " + logValue);
System.out.println("");
// Use of pow() method
double b = 10, e = 2;
double power = StrictMath.pow(b, e);
System.out.println("Use of pow() : " + power);
}
}
输出:
Incremented value of f1 : 31
Incremented value of f2 : -55
Log10 value of 10 : 1.0
Use of pow() : 100.0
19。signum():Java . lang . strict math . signum()方法返回传递的参数的 signum 值。
-1 if x < 0
signum fun(x) = 0 if x = 0
1 if x > 0
注:
结果是 Nan,如果通过了论证就是 NaN。
语法:
public static double signum(double x)
or
public static float signum(float x)
Parameters:
x - the argument whose signum value we need
Returns:
signum value of x
20。max():Java . lang . strict math . max(double v1,double v2) 方法返回两个传递的参数值中较大的值。 这种方法只是比较使用量级,不考虑任何符号。
语法:
public static double max(double v1, double v2)
Parameters:
v1 - first value
v2 - second value
Returns:
v1 or v2 based on which number is greater.
It can return either of the two if v1 = v2\.
21。round():Java . lang . strict math . round()方法将传递的参数四舍五入到最接近的小数位。
注意:结果为 0,如果自变量为 NaN。
语法:
public static long round(long arg)
or
public static double round(double arg)
Parameters:
arg - argument needs to round off
Returns:
round off value of the argument
Java 代码解释 lang 中 signum(),round(),max()方法。StrictMath 类。
Java 语言(一种计算机语言,尤用于创建网站)
// Java code explaining the lang.StrictMath Class methods
// signum(), round(), max()
import java.lang.*;
public class NewClass
{
public static void main(String args[])
{
// Use of signum() method
double x = 10.4556, y = -23.34789;
double signm = StrictMath.signum(x);
System.out.println("Signum of 10.45 = " + signm);
signm = StrictMath.signum(y);
System.out.println("Signum of -23.34 = " + signm);
System.out.println("");
// Use of round() method
double r1 = StrictMath.round(x);
System.out.println("Round off 10.4556 = " + r1);
double r2 = StrictMath.round(y);
System.out.println("Round off 23.34789 = " + r2);
System.out.println("");
// Use of max() method on r1 and r2
double m = StrictMath.max(r1, r2);
System.out.println("Max b / w r1 and r2 = " + r2);
}
}
输出:
Signum of 10.45 = 1.0
Signum of -23.34 = -1.0
Round off 10.4556 = 10.0
Round off 23.34789 = -23.0
Max b/w r1 and r2 = -23.0
22。方法返回最小精度单位 ie。两个浮点数之间的最小距离。 这里,是最小距离 b/w 的自变量和下一个较大的值。
语法:
public static double ulp(double arg)
or
public static float ulp(float arg)
Parameters:
arg - argument passed.
Returns:
least distance b/w the argument and next larger value.
23。log1p():Java . lang . strict math . log1p()方法返回(传递的参数+ 1)的自然对数。
语法:
public static double log1p(double arg)
Parameters:
arg - the argument
Returns:
log of (argument + 1).
This result is within 1 unit in the last place of exact result.
Java 代码,解释 lang 中的 ulp(),log1p()方法。StrictMath 类。
Java 语言(一种计算机语言,尤用于创建网站)
// Java code explaining the lang.StrictMath Class methods
// ulp(), log1p()
import java.lang.*;
public class NewClass
{
public static void main(String args[])
{
// Use of ulp() method
double x = 34.652, y = -23.34789;
double u = StrictMath.ulp(x);
System.out.println("ulp of 34.652 : " + u);
u = StrictMath.ulp(y);
System.out.println("ulp of -23.34789 : " + u);
System.out.println("");
// Use of log() method
double l = 99;
double l1 = StrictMath.log1p(l);
System.out.println("Log of (1 + 99) : " + l1);
l1 = StrictMath.log(100);
System.out.println("Log of 100 : " + l1);
}
}
输出:
ulp of 34.652 : 7.105427357601002E-15
ulp of -23.34789 : 3.552713678800501E-15
Log of (1 + 99) : 4.605170185988092
Log of 100 : 4.605170185988092
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