C# 程序读取字符串并求所有数字的和
原文:https://www . geesforgeks . org/c-sharp-程序读取字符串并查找所有数字的总和/
给定一个字符串，我们的任务是首先从用户那里读取这个字符串，然后找到给定字符串中所有数字的总和。
示例
Input : abc23d4
Output: 9
Input : 2a3hd5j
Output: 10
方法:
要读取字符串并找到字符串中所有数字的总和，请遵循以下步骤:
- First, we use the console to read strings from users. The ReadLine () method.
- Initializes an integer sum with a value of 0.
- Now iterate over the string until the end.
- If the character value is greater than or equal to "0" and less than or equal to "9" (that is, the ascii value is between 48 and 57), the character-"0" (which gives the character value) is executed and added to the sum.
- Sum now contains the sum value of all the numbers in the string.
例:
c
// C# program to read the string from the user and
// then find the sum of all digits in the string
using System;
class GFG{
public static void Main()
{
string str;
Console.WriteLine("Enter a string ");
// Reading the string from user.
str = Console.ReadLine();
int count, sum = 0;
int n = str.Length;
for(count = 0; count < n; count++)
{
// Checking if the string contains digits or not
// If yes then add the numbers to find their sum
if ((str[count] >= '0') && (str[count] <= '9'))
{
sum += (str[count] - '0');
}
}
Console.WriteLine("Sum = " + sum);
}
}
产出 1:
Enter a string
abc23d4
Sum = 9
输出 2:
Enter a string
2a3hd5j
Sum = 10
说明:在上面的例子中，首先我们读取字符串，我们将迭代每个字符，并通过比较字符的 ASCII 值来检查该字符是否为整数。如果字符是整数，则将该值加到总和中。迭代结束时，sum 变量将包含字符串中数字的总和。
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