Java 中的整数逆向()方法
原文:https://www . geesforgeks . org/integer-reverse-method-in-Java/
java.lang.Integer.reverse()是 java 中的一个内置方法，用于返回指定 int 值的二进制补码表示形式中位的逆序。
语法:
public static int reverse(*int a*)
参数:参数 a 是一个整数值，其位将被反转。
返回值:该方法返回通过反转指定 int 值中的位的顺序而获得的值。
示例:
Input: 86
Output: 1778384896
Explanation:
Consider an integer a = 86
Binary Representation = 1010110
The number of one bit = 4
After reversing it is = 1778384896
Input: 168
Output: 352321536
下面的程序说明了 java.lang.Integer.reverse()方法: 程序 1: 为正数。
// Java program to illustrate the
// Java.lang.Integer.reverse() method
import java.lang.*;
public class geeks {
public static void main(String[] args)
{
int a = 168;
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits
System.out.println("By reversing we get = " + Integer.reverse(a));
}
}
Output:
Number = 168
By reversing we get = 352321536
程序 2: 为负数。
// Java program to illustrate the
// Java.lang.Integer.reverse() method
import java.lang.*;
public class geeks {
public static void main(String[] args)
{
int a = -72;
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits
System.out.println("By reversing we get = " + Integer.reverse(a));
}
}
Output:
Number = -72
By reversing we get = 503316479
程序 3: 为十进制值和字符串。 注意:当十进制值或字符串作为参数传递时，它会抛出一条错误消息。
// Java program to illustrate the
// Java.lang.Integer.reverse() method
import java.lang.*;
public class geeks {
public static void main(String[] args)
{
int a = 37.9;
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits in
// the specified int value
System.out.println("By reversing we get = " + Integer.reverse(a));
a = "21";
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits in
// the specified int value
System.out.println("By reversing we get = " + Integer.reverse(a));
}
}
Output:
prog.java:9: error: incompatible types: possible lossy conversion from double to int
int a = 37.9;
^
prog.java:17: error: incompatible types: String cannot be converted to int
a = "21";
^
2 errors
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