Java 中的整数. numberOfTrailingZeros()方法，示例
原文:https://www . geesforgeks . org/integer-number of trailing zeros-in-Java-method-with-example/
Java . lang . integer . number of trailing zeros()是返回最低位(即)之后的零(0)位总数的方法。最右边或最低有效的“1”位)指定整数值的二进制补码表示中的一位，或者我们可以说它是将 int 值转换为 binary 的函数，然后考虑最低的一位，并返回其后面的零位数。如果指定的整数值在其二进制补码表示中没有一位，换句话说，如果它等于零，那么它将返回 32。
语法:
public static int numberOfTrailingZeros(int a)
参数:参数 a 为整数值。
返回值:该方法返回指定 int 值的二进制补码二进制表示中最低一位或设置位之后的零位数，如果该值等于零，则返回 32。
解释
- 考虑 a = 170 的整数
- 二进制表示= 10101010
- 最低一位= 2
- 尾随零的数量= 1
下面的程序说明了 Java . lang . integer . numberoftrailingzeros()方法。
程序 1: 为正数。
// Java program to illustrate the
// Java.lang.Integer.numberOfTrailingZeros() method
import java.lang.*;
public class TrailingZeros {
public static void main(String[] args) {
int a = 155;
System.out.println("Integral Number = " + a);
// Returns the number of zero bits following the lowest-order
//rightmost one-bit
System.out.print("Number of Trailing Zeros = ");
System.out.println(Integer.numberOfTrailingZeros(a));
a = 24;
System.out.println("Integral Number = " + a);
// Returns the number of zero bits following the lowest-order
//rightmost one-bit
System.out.print("Number of Trailing Zeros = ");
System.out.println(Integer.numberOfTrailingZeros(a));
}
}
Output:
Integral Number = 155
Number of Trailing Zeros = 0
Integral Number = 24
Number of Trailing Zeros = 3
注意:这里尾随零的数量等于 0，表示 155，这是因为在二进制表示 10011011 中，没有零跟随最低阶(即。最右边或最低有效“1”位)一位。
程序 2: 为负数。
// Java program to illustrate the
// Java.lang.Integer.numberOfTrailingZeros() method
import java.lang.*;
public class TrailingZeros {
public static void main(String[] args) {
int a = -1;
System.out.println("Integral Number = " + a);
// Returns the number of zero bits following the lowest-order
//rightmost one-bit
System.out.print("Number of Trailing Zeros = ");
System.out.println(Integer.numberOfTrailingZeros(a));
a = -90;
System.out.println("Integral Number = " + a);
// Returns the number of zero bits following the lowest-order
//rightmost one-bit
System.out.print("Number of Trailing Zeros = ");
System.out.println(Integer.numberOfTrailingZeros(a));
}
}
Output:
Integral Number = -1
Number of Trailing Zeros = 0
Integral Number = -90
Number of Trailing Zeros = 1
程序 3: 为十进制值。 注意:当十进制值作为参数传递时，它会返回一条错误消息。
// Java program to illustrate the
// Java.lang.Integer.numberOfTrailingZeros() method
import java.lang.*;
public class TrailingZeros {
public static void main(String[] args) {
System.out.println("Number of trailing zeros = "+
Integer.numberOfTrailingZeros(12.66));
}
}
输出:
prog.java:10: error: incompatible types: possible lossy conversion from double to int
Integer.numberOfTrailingZeros(12.66));
^
Note: Some messages have been simplified; recompile with
-Xdiags:verbose to get full output
1 error
程序 4: 为字符串值。 注意:当字符串值作为参数传递时，它会返回一条错误消息。
// Java program to illustrate the
// Java.lang.Integer.numberOfTrailingZeros() method
import java.lang.*;
public class TrailingZeros {
public static void main(String[] args) {
System.out.println("Number of trailing zeros = "
+ Integer.numberOfTrailingZeros("12"));
}
}
输出:
prog.java:10: error: incompatible types: String cannot be converted to int
+ Integer.numberOfTrailingZeros("12"));
^
Note: Some messages have been simplified; recompile with
-Xdiags:verbose to get full output
1 error
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