检查字符串的平均字符是否存在
给定一个字母数字字符串，任务是检查该字符串的平均字符是否存在。平均字符是指与 ASCII 值相对应的字符，它是字符串中所有字符的 ASCII 值平均值的下限。
示例:
Input: abcdef
Output: d
Yes
Explanation:
string = "abcdef"
ASCII values of a = 97, b=98,
c=99, d=100, e=101, f=101
Sum of these values is 597
Average is 99.5 ~ 100
Character of ASCII value 100 = d
Hence d is present in the string.
Input: MNFGH
Output: J
No
方法:解决这个问题的方法很简单。可以通过以下步骤解决:
- 找出给定字符串中所有字符的 ASCII 值之和。
- 将 ASCII 值的平均值作为平均值=(总和/字符数)
- 获取这个平均 ASCII 值的字符。打印此字符
- 检查字符串中是否存在该字符。相应地打印是或否。
下面是上述方法的实现:
执行:
C++
// CPP program to check if the average character
// is present in the string or not
#include <bits/stdc++.h>
#include <math.h>
using namespace std;
// Checks if the character is present
bool check_char(char* st, char ch)
{
// Get the length of string
int l = strlen(st);
// Iterate from i=0 to
// the length of the string
// to check if the character
// is present in the string
for (int i = 0; i < l; i++) {
if (st[i] == ch)
return true;
}
return false;
}
// Finds the average character of the string
char find_avg(char* st)
{
int i, sm = 0;
int l = strlen(st);
char ch;
for (i = 0; i < l; i++) {
ch = st[i];
// Calculate the sum of ASCII
// values of each character
sm = sm + (int)(ch);
}
// Calculate average of ascii values
int avg = (int)(floor(sm / l));
// Convert the ASCII value to character
// and return it
return ((char)(avg));
}
// Driver code
int main()
{
char st[] = "ag23sdfa";
// Get the average character
char ch = find_avg(st);
cout << ch << endl;
// Check if the average character
// is present in string or not
if (check_char(st, ch) == true)
cout << "Yes";
else
cout << "No";
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to check if the average character
// is present in the string or not
import java.math.*;
class GFG {
// Checks if the character is present
static boolean check_char(String st, char ch)
{
// Get the length of string
int l = st.length();
// Iterate from i=0 to
// the length of the string
// to check if the character
// is present in the string
for (int i = 0; i < l; i++) {
if (st.charAt(i) == ch)
return true;
}
return false;
}
// Finds the average character of the string
static char find_avg(String st)
{
int i, sm = 0;
int l = st.length();
char ch;
for (i = 0; i < l; i++) {
ch = st.charAt(i);
// Calculate the sum of ASCII
// values of each character
sm = sm + (int)(ch);
}
// Calculate the average of ASCII values
int avg = (int)(Math.floor(sm / l));
// Convert the ASCII value to character
// and return it
return ((char)(avg));
}
// Driver code
public static void main(String[] args)
{
String st = "ag23sdfa";
// Get the average character
char ch = find_avg(st);
System.out.println(ch);
// Check if the average character
// is present in string or not
if (check_char(st, ch) == true)
System.out.println("Yes");
else
System.out.println("No");
}
}
Python 3
# Python 3 program to check if the average
# character is present in the string or not
from math import floor
# Checks if the character is present
def check_char(st, ch):
# Get the length of string
l = len(st)
# Iterate from i=0 to
# the length of the string
# to check if the character
# is present in the string
for i in range(l):
if (st[i] == ch):
return True
return False
# Finds the average character
# of the string
def find_avg(st):
sm = 0
l = len(st)
for i in range(l):
ch = st[i]
# Calculate the sum of ASCII
# values of each character
sm = sm + ord(ch)
# Calculate average of ascii values
avg = int(floor(sm / l))
# Convert the ASCII value to character
# and return it
return (chr(avg))
# Driver code
if __name__ == '__main__':
st = "ag23sdfa"
# Get the average character
ch = find_avg(st)
print(ch)
# Check if the average character
# is present in string or not
if (check_char(st, ch) == True):
print("Yes")
else:
print("No")
# This code is contributed by
# Surendra_Gangwar
C
// C# program to check if the average character
// is present in the string or not
using System;
class GFG
{
// Checks if the character is present
static bool check_char(string st, char ch)
{
// Get the length of string
int l = st.Length;
// Iterate from i=0 to
// the length of the string
// to check if the character
// is present in the string
for (int i = 0; i < l; i++)
{
if (st[i] == ch)
return true;
}
return false;
}
// Finds the average character of the string
static char find_avg(string st)
{
int i, sm = 0;
int l = st.Length;
char ch;
for (i = 0; i < l; i++)
{
ch = st[i];
// Calculate the sum of ASCII
// values of each character
sm = sm + (int)(ch);
}
// Calculate the average of ASCII values
int avg = (int)(Math.Floor((double)(sm / l)));
// Convert the ASCII value to character
// and return it
return ((char)(avg));
}
// Driver code
public static void Main()
{
string st = "ag23sdfa";
// Get the average character
char ch = find_avg(st);
Console.WriteLine(ch);
// Check if the average character
// is present in string or not
if (check_char(st, ch) == true)
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed by Akanksha Rai
Output:
Y
No
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