检查数字是否平衡
给定一个字符串形式的数字 N ，任务是检查给定的数字是否平衡。
平衡数:一个数如果前半部分的位数之和等于后半部分的位数之和，则称该数为平衡数。 注:所有回文号均为平衡号。
示例:
输入: N = 19091 输出:平衡 说明: 中间元素为 0 左半部分之和= 1 + 9 = 10 右半部分之和= 9 + 1 = 10 因此，给定的数字为平衡数。
输入: N = 133423 输出:不平衡 解释: 左半部分之和= 1 + 3 + 3 (7) 右半部分之和= 4 + 2 + 3 (9) 因此，给定的数字是不平衡的
方法: 从头开始迭代数字的一半长度。将s【I】和 s【位数–1–I】分别加到 leftSum 和 rightSum 上，同时计算前半部分和后半部分的位数之和。最后，检查左总和和右总和是否相等。
下面是上述方法的实现。
C++
// C++ program to check
// if a number is
// Balanced or not
#include <bits/stdc++.h>
using namespace std;
// Function to check whether N is
// Balanced Number or not
void BalancedNumber(string s)
{
int Leftsum = 0;
int Rightsum = 0;
// Calculating the Leftsum
// and rightSum simultaneously
for (int i = 0; i < s.size() / 2; i++) {
// Typecasting each character
// to integer and adding the
// digit to respective sums
Leftsum += int(s[i] - '0');
Rightsum += int(s[s.size() - 1 - i]
- '0');
}
if (Leftsum == Rightsum)
cout << "Balanced" << endl;
else
cout << "Not Balanced" << endl;
}
// Driver Code
int main()
{
string s = "12321";
// Function call
BalancedNumber(s);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to check if a number
// is Balanced or not
import java.io.*;
class GFG{
// Function to check whether N is
// Balanced Number or not
private static void BalancedNumber(String s)
{
int Leftsum = 0;
int Rightsum = 0;
// Calculating the Leftsum
// and rightSum simultaneously
for(int i = 0; i < s.length() / 2; i++)
{
// Typecasting each character
// to integer and adding the
// digit to respective sums
Leftsum += (int)(s.charAt(i) - '0');
Rightsum += (int)(s.charAt(
s.length() - 1 - i) - '0');
}
if (Leftsum == Rightsum)
System.out.println("Balanced");
else
System.out.println("Not Balanced");
}
// Driver Code
public static void main (String[] args)
{
String s = "12321";
// Function call
BalancedNumber(s);
}
}
// This code is contributed by jithin
Python 3
# Python3 program to check
# if a number is
# Balanced or not
# Function to check whether N is
# Balanced Number or not
def BalancedNumber(s):
Leftsum = 0
Rightsum = 0
# Calculating the Leftsum
# and rightSum simultaneously
for i in range(0, int(len(s) / 2)):
# Typecasting each character
# to integer and adding the
# digit to respective sums
Leftsum = Leftsum + int(s[i])
Rightsum = (Rightsum +
int(s[len(s) - 1 - i]))
if (Leftsum == Rightsum):
print("Balanced", end = '\n')
else:
print("Not Balanced", end = '\n')
# Driver Code
s = "12321"
# Function call
BalancedNumber(s)
# This code is contributed by PratikBasu
C
// C# program to check
// if a number is
// Balanced or not
using System;
class GFG{
// Function to check whether N is
// Balanced Number or not
static void BalancedNumber(string s)
{
int Leftsum = 0;
int Rightsum = 0;
// Calculating the Leftsum
// and rightSum simultaneously
for (int i = 0; i < s.Length / 2; i++)
{
// Typecasting each character
// to integer and adding the
// digit to respective sums
Leftsum += (int)(Char.GetNumericValue(s[i]) -
Char.GetNumericValue('0'));
Rightsum += (int)(Char.GetNumericValue(s[s.Length -
1 - i]) -
Char.GetNumericValue('0'));
}
if (Leftsum == Rightsum)
Console.WriteLine("Balanced");
else
Console.WriteLine("Not Balanced");
}
// Driver code
static void Main()
{
string s = "12321";
// Function call
BalancedNumber(s);
}
}
// This code is contributed by divyeshrabadiya07
java 描述语言
<script>
// JavaScript program to check if a number
// is Balanced or not
// Function to check whether N is
// Balanced Number or not
function BalancedNumber(s)
{
let Leftsum = 0;
let Rightsum = 0;
// Calculating the Leftsum
// and rightSum simultaneously
for(let i = 0; i < s.length / 2; i++)
{
// Typecasting each character
// to integer and adding the
// digit to respective sums
Leftsum += (s[i] - '0');
Rightsum += (s[
s.length - 1 - i] - '0');
}
if (Leftsum == Rightsum)
document.write("Balanced");
else
document.write("Not Balanced");
}
// Driver Code
let s = "12321";
// Function call
BalancedNumber(s);
</script>
Output:
Balanced
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