从字符串中找到网站的唯一标识和域名
原文:https://www . geesforgeks . org/find-unique-id-和-域名-网站-从字符串中提取/
给定一个由唯一网站的唯一 ID 和 域名 组成的大小为 N 的字符串 S ，如果 ID 的形式为【char，char，char，char，char，digit，digit，digit，digit，char
示例:
输入: S =“感谢 ABCDE1234F 访问我们并购买产品项目 AMZrr@！k .欲了解更多优惠，请访问我们的网站: 输出: ID =abcde 1234 f Domain = Amazon.com
*输入:* S = "Hi PQRST5678D，很荣幸能招待您。查看 www.oyo.com，我们未来停留的官方网站“ 输出: ID =pqrst 5678d 域名= oyo.com****
**方法:解决给定问题最简单的方法是将字符串拆分成单词并查找拆分后的字符串是 ID 还是 Domain 。按照以下步骤解决问题:****
- *首先将字符串中由空格分隔的单词拆分并存储在字符串的向量中，说*单词[] 。****
- *初始化两个空字符串，说 *ID 和域名来存储结果 ID 和域名。****
-
*遍历字符串的向量 *单词[] ，并执行以下步骤:
*下面是上述方法的实现:*
*C++*
**// C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;
// Function to check if a character is
// alphabet or not
bool ischar(char x)
{
if ((x >= 'A' && x <= 'Z')
|| (x >= 'a' && x <= 'z')) {
return 1;
}
return 0;
}
// Function to check if a character is
// a numeric or not
bool isnum(char x)
{
if (x >= '0' && x <= '9')
return 1;
return 0;
}
// Function to find ID and Domain
// name from a given string
void findIdandDomain(string S, int N)
{
// Stores ID and the domain names
string ID, Domain;
// Stores the words of string S
vector<string> words;
// Stores the temporary word
string curr = "";
// Traverse the string S
for (int i = 0; i < N; i++) {
// If the current character
// is space
if (S[i] == ' ') {
// Push the curr in words
words.push_back(curr);
// Update the curr
curr = "";
}
// Otherwise
else {
if (S[i] == '.') {
if (i + 1 == N
|| (i + 1 < N
&& S[i + 1] == ' '))
continue;
}
curr += S[i];
}
}
// If curr is not empty
if (curr.length())
words.push_back(curr);
for (string ss : words) {
// If length of ss is 10
if (ss.size() == 10) {
bool flag = 0;
// Traverse the string ss
for (int j = 0; j <= 9; j++) {
// If j is in the range
// [5, 9)
if (j >= 5 && j < 9) {
// If current character
// is not numeric
if (isnum(ss[j]) == 0)
// Mark flag 1
flag = 1;
}
// Otherwise
else {
// If current character
// is not alphabet
if (ischar(ss[j]) == 0)
// Mark flag 1
flag = 1;
}
}
// If flag is false
if (!flag) {
// Assign ss to ID
ID = ss;
}
}
// If substring formed by the
// first 3 character is "www"
// and last 3 character is "moc"
if (ss.substr(0, 3) == "www"
&& ss.substr(
ss.length() - 3, 3)
== "com") {
// Update the domain name
Domain = ss.substr(
4, ss.size() - 4);
}
}
// Print ID and Domain
cout << "ID = " << ID
<< endl;
cout << "Domain = " << Domain;
}
// Driver Code
int main()
{
string S = "We thank ABCDE1234F for visiting "
"us and buying "
"products item AMZrr@!k. For more "
"offers, visit "
"us at www.amazon.com";
int N = S.length();
findIdandDomain(S, N);
return 0;
}**
*Java 语言(一种计算机语言，尤用于创建网站)*
**// Java program for the above approach
import java.util.*;
class GFG{
// Function to check if a character is
// alphabet or not
static boolean ischar(char x)
{
if ((x >= 'A' && x <= 'Z') ||
(x >= 'a' && x <= 'z'))
{
return true;
}
return false;
}
// Function to check if a character is
// a numeric or not
static boolean isnum(char x)
{
if (x >= '0' && x <= '9')
return true;
return false;
}
// Function to find ID and Domain
// name from a given String
static void findIdandDomain(String S, int N)
{
// Stores ID and the domain names
String ID = "", Domain = "";
// Stores the words of String S
Vector<String> words = new Vector<String>();
// Stores the temporary word
String curr = "";
// Traverse the String S
for(int i = 0; i < N; i++)
{
// If the current character
// is space
if (S.charAt(i) == ' ')
{
// Push the curr in words
words.add(curr);
// Update the curr
curr = "";
}
// Otherwise
else
{
if (S.charAt(i) == '.')
{
if (i + 1 == N || (i + 1 < N &&
S.charAt(i + 1) == ' '))
continue;
}
curr += S.charAt(i);
}
}
// If curr is not empty
if (curr.length() > 0)
words.add(curr);
for(String ss : words)
{
// If length of ss is 10
if (ss.length() == 10)
{
boolean flag = false;
// Traverse the String ss
for(int j = 0; j <= 9; j++)
{
// If j is in the range
// [5, 9)
if (j >= 5 && j < 9)
{
// If current character
// is not numeric
if (isnum(ss.charAt(j)) == false)
// Mark flag 1
flag = true;
}
// Otherwise
else
{
// If current character
// is not alphabet
if (ischar(ss.charAt(j)) == false)
// Mark flag 1
flag = true;
}
}
// If flag is false
if (!flag)
{
// Assign ss to ID
ID = ss;
}
}
// If subString formed by the
// first 3 character is "www"
// and last 3 character is "moc"
if (ss.length() > 2 && ss.substring(0, 3).equals("www") &&
ss.substring(ss.length() - 3).equals("com"))
{
// Update the domain name
Domain = ss.substring(4, ss.length());
}
}
// Print ID and Domain
System.out.print("ID = " + ID + "\n");
System.out.print("Domain = " + Domain);
}
// Driver Code
public static void main(String[] args)
{
String S = "We thank ABCDE1234F for visiting " +
"us and buying products item AMZrr@!k. " +
"For more offers, visit us at www.amazon.com";
int N = S.length();
findIdandDomain(S, N);
}
}
// This code is contributed by 29AjayKumar**
*Python 3*
**# Python3 program for the above approach
# Function to check if a character is
# alphabet or not
def ischar(x):
if ((x >= 'A' and x <= 'Z') or
(x >= 'a' and x <= 'z')):
return 1
return 0
# Function to check if a character is
# a numeric or not
def isnum(x):
if (x >= '0' and x <= '9'):
return 1
return 0
# Function to find ID and Domain
# name from a given
def findIdandDomain(S, N):
# Stores ID and the domain names
ID, Domain = "", ""
# Stores the words of S
words = []
# Stores the temporary word
curr = ""
# Traverse the S
for i in range(N):
# If the current character
# is space
if (S[i] == ' '):
# Push the curr in words
words.append(curr)
# Update the curr
curr = ""
# Otherwise
else:
if (S[i] == '.'):
if (i + 1 == N or (i + 1 < N and
S[i + 1] == ' ')):
continue
curr += S[i]
# If curr is not empty
if (len(curr)):
words.append(curr)
for ss in words:
# If length of ss is 10
if (len(ss) == 10):
flag = 0
# Traverse the ss
for j in range(10):
# If j is in the range
# [5, 9)
if (j >= 5 and j < 9):
# If current character
# is not numeric
if (isnum(ss[j]) == 0):
# Mark flag 1
flag = 1
# Otherwise
else:
# If current character
# is not alphabet
if (ischar(ss[j]) == 0):
# Mark flag 1
flag = 1
# If flag is false
if (not flag):
# Assign ss to ID
ID = ss
# If sub formed by the
# first 3 character is "www"
# and last 3 character is "moc"
if (ss[0: 3] == "www" and ss[len(ss) - 3: ]== "com"):
# Update the domain name
Domain = ss[4: len(ss) ]
# Print ID and Domain
print("ID =", ID)
print("Domain =", Domain)
# Driver Code
if __name__ == '__main__':
S = "We thank ABCDE1234F for visiting us "\
"and buying products item AMZrr@!k. "\
"For more offers, visit us at www.amazon.com"
N = len(S)
findIdandDomain(S, N)
# This code is contributed by mohit kumar 29**
*C#*
**// C# program for the above approach
using System;
using System.Collections.Generic;
public class GFG
{
// Function to check if a character is
// alphabet or not
static bool ischar(char x)
{
if ((x >= 'A' && x <= 'Z') ||
(x >= 'a' && x <= 'z'))
{
return true;
}
return false;
}
// Function to check if a character is
// a numeric or not
static bool isnum(char x)
{
if (x >= '0' && x <= '9')
return true;
return false;
}
// Function to find ID and Domain
// name from a given String
static void findIdandDoMain(String S, int N)
{
// Stores ID and the domain names
String ID = "", Domain = "";
// Stores the words of String S
List<String> words = new List<String>();
// Stores the temporary word
String curr = "";
// Traverse the String S
for(int i = 0; i < N; i++)
{
// If the current character
// is space
if (S[i] == ' ')
{
// Push the curr in words
words.Add(curr);
// Update the curr
curr = "";
}
// Otherwise
else
{
if (S[i] == '.')
{
if (i + 1 == N || (i + 1 < N &&
S[i + 1] == ' '))
continue;
}
curr += S[i];
}
}
// If curr is not empty
if (curr.Length > 0)
words.Add(curr);
foreach(String ss in words)
{
// If length of ss is 10
if (ss.Length == 10)
{
bool flag = false;
// Traverse the String ss
for(int j = 0; j <= 9; j++)
{
// If j is in the range
// [5, 9)
if (j >= 5 && j < 9)
{
// If current character
// is not numeric
if (isnum(ss[j]) == false)
// Mark flag 1
flag = true;
}
// Otherwise
else
{
// If current character
// is not alphabet
if (ischar(ss[j]) == false)
// Mark flag 1
flag = true;
}
}
// If flag is false
if (!flag)
{
// Assign ss to ID
ID = ss;
}
}
// If subString formed by the
// first 3 character is "www"
// and last 3 character is "moc"
if (ss.Length > 2 && ss.Substring(0, 3).Equals("www") &&
ss.Substring(ss.Length - 3).Equals("com"))
{
// Update the domain name
Domain = ss.Substring(4, ss.Length-4);
}
}
// Print ID and Domain
Console.Write("ID = " + ID + "\n");
Console.Write("Domain = " + Domain);
}
// Driver Code
public static void Main(String[] args)
{
String S = "We thank ABCDE1234F for visiting " +
"us and buying products item AMZrr@!k. " +
"For more offers, visit us at www.amazon.com";
int N = S.Length;
findIdandDoMain(S, N);
}
}
// This code is contributed by 29AjayKumar**
*java 描述语言*
**<script>
// JavaScript program for the above approach
// Function to check if a character is
// alphabet or not
function ischar(x)
{
if ((x >= 'A' && x <= 'Z') ||
(x >= 'a' && x <= 'z'))
{
return true;
}
return false;
}
// Function to check if a character is
// a numeric or not
function isnum(x)
{
if (x >= '0' && x <= '9')
return true;
return false;
}
// Function to find ID and Domain
// name from a given string
function findIdandDomain(S, N)
{
// Stores ID and the domain names
let ID, Domain;
// Stores the words of string S
let words = [];
// Stores the temporary word
let curr = "";
// Traverse the string S
for(let i = 0; i < N; i++)
{
// If the current character
// is space
if (S[i] == ' ')
{
// Push the curr in words
words.push(curr);
// Update the curr
curr = "";
}
// Otherwise
else
{
if (S[i] == '.')
{
if (i + 1 == N ||
(i + 1 < N && S[i + 1] == ' '))
continue;
}
curr += S[i];
}
}
// If curr is not empty
if (curr.length >= 1)
words.push(curr);
for(let i = 0; i < words.length; i++)
{
// If length of ss is 10
if (words[i].length == 10)
{
let flag = 0;
// Traverse the string ss
for(let j = 0; j <= 9; j++)
{
// If j is in the range
// [5, 9)
if (j >= 5 && j < 9)
{
// If current character
// is not numeric
if (isnum(words[i][j]) == 0)
// Mark flag 1
flag = 1;
}
// Otherwise
else
{
// If current character
// is not alphabet
if (ischar(words[i][j]) == 0)
// Mark flag 1
flag = 1;
}
}
// If flag is false
if (!flag)
{
// Assign ss to ID
ID = words[i];
}
}
// If substring formed by the
// first 3 character is "www"
// and last 3 character is "moc"
if (words[i].substring(0, 3) == "www" &&
words[i].substring(
words[i].length - 3) == "com")
{
// Update the domain name
Domain = words[i].substring(4);
}
}
// Print ID and Domain
document.write("ID = " + ID + "<br>");
document.write("Domain = " + Domain);
}
// Driver Code
let S = "We thank ABCDE1234F for visiting " +
"us and buying products item AMZrr@!k. " +
"For more offers, visit us at www.amazon.com";
let N = S.length;
findIdandDomain(S, N);
// This code is contributed by Dharanendra L V.
</script>**
**Output:
ID = ABCDE1234F
Domain = amazon.com****
*时间复杂度:O(N) T5辅助空间: O(N)*
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