找出回文的时间，该时间在给定时间
之后
原文:https://www . geesforgeks . org/find-the-time-of-is-回文并在给定时间后出现/
给定一个以 24 小时格式存储时间的字符串 str 为 HH:MM ，使得 0 ≤ HH ≤ 23 和 0 ≤ MM ≤ 59 。任务是找到下一个最近的时间，当作为字符串读取时，这是一个回文。如果不存在这样的字符串，则打印 -1 。 举例:
输入: str = "21:12" 输出: 22:22 给定小时内唯一可能的回文时间为 21:12 但不大于给定时间，因此输出将为 下一小时的回文时间，即 22:22 输入: str = "23:32" 输出:--
方法:有三种可能的情况:
- 如果 MM <反转(HH) 则输出为 HH 小时，反转(HH) 分钟。
- 如果HH = 23MM≥32，则输出为 00:00，即上午 12:00。
- 否则输出将是 HH + 1 小时，反转(HH + 1) 分钟。
以下是上述方法的实现:
C++
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
// Function to return the required time
string getTime(string s, int n)
{
// To store the resultant time
string res;
// Hours are stored in h as integer
int h = stoi(s.substr(0, 2));
// Minutes are stored in m as integer
int m = stoi(s.substr(3, 2));
// Reverse of h
int rev_h = (h % 10) * 10 + ((h % 100) - (h % 10)) / 10;
// Reverse of h as a string
string rev_hs = to_string(rev_h);
if (h == 23 && m >= 32) {
res = "-1";
}
// If MM < reverse of (HH)
else if (m < rev_h) {
string temp;
// 0 is added if HH < 10
if (h < 10)
temp = "0";
temp = temp + to_string(h);
// 0 is added if rev_h < 10
if (rev_h < 10)
res = res + temp + ":0" + rev_hs;
else
res = res + temp + ":" + rev_hs;
}
else {
// Increment hours
h++;
// Reverse of the hour after incrementing 1
rev_h = (h % 10) * 10 + ((h % 100) - (h % 10)) / 10;
rev_hs = to_string(rev_h);
string temp;
// 0 is added if HH < 10
if (h < 10)
temp = "0";
temp = temp + to_string(h);
// 0 is added if rev_h < 10
if (rev_h < 10)
res = res + temp + ":0" + rev_hs;
else
res = res + temp + ":" + rev_hs;
}
return res;
}
// Driver code
int main()
{
string s = "21:12";
int n = s.length();
cout << getTime(s, n);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java implementation of the approach
import java.util.*;
class GFG
{
// Function to return the required time
static String getTime(String s, int n)
{
// To store the resultant time
String res = "";
// Hours are stored in h as integer
int h = Integer.parseInt(s.substring(0, 0 + 2));
// Minutes are stored in m as integer
int m = Integer.parseInt(s.substring(3, 3 + 2));
// Reverse of h
int rev_h = (h % 10) * 10 +
((h % 100) - (h % 10)) / 10;
// Reverse of h as a string
String rev_hs = Integer.toString(rev_h);
if (h == 23 && m >= 32)
{
res = "-1";
}
// If MM < reverse of (HH)
else if (m < rev_h)
{
String temp = "";
// 0 is added if HH < 10
if (h < 10)
temp = "0";
temp = temp + Integer.toString(h);
// 0 is added if rev_h < 10
if (rev_h < 10)
res = res + temp + ":0" + rev_hs;
else
res = res + temp + ":" + rev_hs;
}
else
{
// Increment hours
h++;
// Reverse of the hour after incrementing 1
rev_h = (h % 10) * 10 + ((h % 100) -
(h % 10)) / 10;
rev_hs = Integer.toString(rev_h);
String temp = "";
// 0 is added if HH < 10
if (h < 10)
temp = "0";
temp = temp + Integer.toString(h);
// 0 is added if rev_h < 10
if (rev_h < 10)
res = res + temp + ":0" + rev_hs;
else
res = res + temp + ":" + rev_hs;
}
return res;
}
// Driver Code
public static void main(String[] args)
{
String s = "21:12";
int n = s.length();
System.out.println(getTime(s, n));
}
}
// This code is contributed by
// sanjeev2552
Python 3
# Python3 implementation of the approach
# Function to return the required time
def getTime(s, n) :
# Hours are stored in h as integer
h = int(s[0 : 2]);
# Minutes are stored in m as integer
m = int(s[3 : 5]);
# Reverse of h
rev_h = (h % 10) * 10 + ((h % 100) - (h % 10)) // 10;
# Reverse of h as a string
rev_hs = str(rev_h)
temp = ""
res = ""
if (h == 23 and m >= 32) :
res = "-1";
# If MM < reverse of (HH)
elif (m < rev_h) :
# 0 is added if HH < 10
if (h < 10) :
temp = "0";
temp = temp + str(h);
# 0 is added if rev_h < 10
if (rev_h < 10) :
res = res + temp + ":0" + rev_hs;
else :
res = res + temp + ":" + rev_hs;
else :
# Increment hours
h += 1
# Reverse of the hour after incrementing 1
rev_h = (h % 10) * 10 + ((h % 100) - (h % 10)) //10;
rev_hs = str(rev_h);
# 0 is added if HH < 10
if (h < 10) :
temp = "0";
temp = temp + str(h);
# 0 is added if rev_h < 10
if (rev_h < 10) :
res = res + temp + ":0" + rev_hs;
else :
res = res + temp + ":" + rev_hs;
return res;
# Driver code
if __name__ == "__main__" :
s = "21:12";
n = len(s);
print(getTime(s, n));
# This code is contributed by AnkitRai01
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
//PHP implementation of the approach
// Function to return the required time
function getTime( $s, $n)
{
// To store the resultant time
$res="";
// Hours are stored in h as integer
$h = intval($s.substr(0, 2));
// Minutes are stored in m as integer
$m = intval($s.substr(3, 2));
// Reverse of h
$rev_h = ($h % 10) * 10 + (($h % 100) - ($h % 10)) / 10;
// Reverse of h as a string
$rev_hs = strval($rev_h);
if ($h == 23 && $m >= 32) {
$res = "-1";
}
// If MM < reverse of (HH)
else if ($m < $rev_h) {
$temp="";
// 0 is added if HH < 10
if ($h < 10)
$temp = "0";
$temp = $temp . strval($h);
// 0 is added if rev_h < 10
if ($rev_h < 10)
$res = $res . $temp . ":0" . $rev_hs;
else
$res = $res. $temp .":" . $rev_hs;
}
else {
// Increment hours
$h++;
// Reverse of the hour after incrementing 1
$rev_h = ($h % 10) * 10 + (($h % 100) - ($h % 10)) / 10;
$rev_hs = strval($rev_h);
$temp="";
// 0 is added if HH < 10
if ($h < 10)
$temp = "0";
$temp = $temp . strval($h);
// 0 is added if rev_h < 10
if ($rev_h < 10)
$res = $res . $temp . ":0" . $rev_hs;
else
$res = $res . $temp . ":" . $rev_hs;
}
return $res;
}
// Driver code
$s = "21:12";
$n = strlen($s);
echo getTime($s, $n);
return 0;
// This code is contributed by ChitraNayal
?>
java 描述语言
<script>
// JavaScript implementation of the approach
// Function to return the required time
function getTime(s,n)
{
// To store the resultant time
let res = "";
// Hours are stored in h as integer
let h = parseInt(s.substring(0, 0 + 2));
// Minutes are stored in m as integer
let m = parseInt(s.substring(3, 3 + 2));
// Reverse of h
let rev_h = (h % 10) * 10 +
((h % 100) - (h % 10)) / 10;
// Reverse of h as a string
let rev_hs = (rev_h).toString();
if (h == 23 && m >= 32)
{
res = "-1";
}
// If MM < reverse of (HH)
else if (m < rev_h)
{
let temp = "";
// 0 is added if HH < 10
if (h < 10)
temp = "0";
temp = temp + h.toString();
// 0 is added if rev_h < 10
if (rev_h < 10)
res = res + temp + ":0" + rev_hs;
else
res = res + temp + ":" + rev_hs;
}
else
{
// Increment hours
h++;
// Reverse of the hour after incrementing 1
rev_h = (h % 10) * 10 + ((h % 100) -
(h % 10)) / 10;
rev_hs = (rev_h).toString();
let temp = "";
// 0 is added if HH < 10
if (h < 10)
temp = "0";
temp = temp + h.toString();
// 0 is added if rev_h < 10
if (rev_h < 10)
res = res + temp + ":0" + rev_hs;
else
res = res + temp + ":" + rev_hs;
}
return res;
}
// Driver Code
let s = "21:12";
let n = s.length;
document.write(getTime(s, n));
// This code is contributed by avanitrachhadiya2155
</script>
Output:
22:22
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