求数列的前 N 项之和 2×3 + 4×4 + 6×5 + 8×6 + …

原文:https://www . geesforgeks . org/find-系列第一个 n 项之和-2x3-4x4-6x5-8x6/

给定一个整数 N 。任务是找到给定系列的总和到 N 项:

2×3 + 4×4 + 6×5 + 8×6 + …

例:

Input : N = 5
Output : Sum = 170

Input : N = 10
Output : Sum = 990

让该系列的第 N 个术语为t_NT5。 t₁= 2×3 =(2×1)(1+2) t₂= 4×4 =(2×2)(2+2) t₃= 6×5 =(2×3)(3+2) t₄= 8×6 =(2×4)(4+2) 。 。 。 t_N=(2×N)(N+2) 级数 N 项之和，****

 Sn = t1 + t2 +... + tn
    =
=
=
=
=
=
=

以下是上述方法的实现:

C++

// C++ program to find sum upto
// N term of the series:
// 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...
#include<iostream>
using namespace std;

// calculate sum upto N term of series
void Sum_upto_nth_Term(int n)
{
    int r = n * (n + 1) *
                (2 * n + 7) / 3;
    cout << r;
}

// Driver code
int main()
{
    int N = 5;
    Sum_upto_nth_Term(N) ;
    return 0;
}

Java 语言(一种计算机语言，尤用于创建网站)

// Java program to find sum upto
// N term of the series:

import java.io.*;

class GFG {
// calculate sum upto N term of series
static void Sum_upto_nth_Term(int n)
{
    int r = n * (n + 1) *
                (2 * n + 7) / 3;
    System.out.println(r);
}

// Driver code
    public static void main (String[] args) {
    int N = 5;
    Sum_upto_nth_Term(N);
    }
}

Python 3

# Python program to find sum upto N term of the series:
# 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...

# calculate sum upto N term of series
def Sum_upto_nth_Term(n):
    return n * (n + 1) * (2 * n + 7) // 3

# Driver code
N = 5
print(Sum_upto_nth_Term(N))

C

// C# program to find sum upto
// N term of the series:
// 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...

using System;

class GFG
{
// calculate sum upto N term of series
static void Sum_upto_nth_Term(int n)
{
    int r = n * (n + 1) *
                (2 * n + 7) / 3;
    Console.Write(r);
}

// Driver code
public static void Main()
{
    int N = 5;
    Sum_upto_nth_Term(N);
}
}

// This code is contributed
// by Akanksha Rai(Abby_akku)

服务器端编程语言（Professional Hypertext Preprocessor 的缩写）

<?php
// PHP program to find sum upto
// N term of the series:
// 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...
function Sum_upto_nth_Term($n)
{
    $r = $n * ($n + 1) *
              (2 * $n + 7) / 3;
    echo $r;
}

// Driver code
$N = 5;
Sum_upto_nth_Term($N);

// This code is contributed
// by Shashank_Sharma
?>

java 描述语言

<script>

// Javascript program to find sum upto
// N term of the series:
// 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...

// calculate sum upto N term of series
function Sum_upto_nth_Term(n)
{
    let r = n * (n + 1) *
                (2 * n + 7) / 3;
    document.write(r);
}

// Driver code

    let N = 5;
    Sum_upto_nth_Term(N) ;

// This code is contributed by Mayank Tyagi

</script>

Output: 

170

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