Java 中的大整数 sqrtAndRemainder()方法，带示例
原文:https://www . geesforgeks . org/big integer-sqrtandreminder-method-in-Java-with-examples/
java.math.BigInteger 。sqrtAndRemainder()方法对调用此方法的当前 BigInteger 执行操作。这个方法是用来计算这个数的整数平方根 (sqrt(this))以及这个数的余数与平方。它返回一个由两个大整数组成的数组，这两个大整数分别包含这个整数的平方根“p”及其余数(这个–p * p)。BigInteger 类内部使用整数数组进行处理，因此对 big integer 对象的操作不如对原语的操作快。
注:此方法自 JDK 9 起可用
语法:
public BigInteger[] sqrtAndRemainder()
参数:该方法不接受参数。
返回值:这个方法返回两个大整数的数组，整数平方根在索引 0，余数在索引 1。
异常:数值必须为正数，否则算法异常被抛出。
下面的程序说明了 BigInteger 类的 sqrtAndRemainder()方法
例 1:
// Java program to demonstrate
// sqrtAndRemainder() method of BigInteger
import java.math.BigInteger;
class Main {
public static void main(String[] args)
{
// BigInteger object to store result
BigInteger res[];
// For user input
// Use Scanner or BufferedReader
// Two object of String created
// Holds the values to perform operation
String input1 = "15";
// Convert the string input to BigInteger
BigInteger a
= new BigInteger(input1);
// Using sqrtAndRemainder() method
try {
res = a.sqrtAndRemainder();
// Display the result
System.out.println("The square root of\n"
+ a + "\nis " + res[0]
+ "\nand remainder is "
+ res[1]);
}
catch (ArithmeticException e) {
System.out.println(e);
}
}
}
输出:
The square root of
15
is 3
and remainder is 6
例 2:
// Java program to demonstrate
// sqrtAndRemainder() method of BigInteger
import java.math.BigInteger;
class Main {
public static void main(String[] args)
{
// BigInteger object to store result
BigInteger res[];
// For user input
// Use Scanner or BufferedReader
// Two object of String created
// Holds the values to perform operation
String input1 = "625";
// Convert the string input to BigInteger
BigInteger a
= new BigInteger(input1);
// Using sqrtAndRemainder() method
try {
res = a.sqrtAndRemainder();
// Display the result
System.out.println("The square root of\n"
+ a + "\nis " + res[0]
+ "\nand remainder is "
+ res[1]);
}
catch (ArithmeticException e) {
System.out.println(e);
}
}
}
输出:
The square root of
625
is 25
and remainder is 0
例 3: 数值为负时显示异常的程序。
// Java program to demonstrate
// sqrtAndRemainder() method of BigInteger
import java.math.BigInteger;
class Main {
public static void main(String[] args)
{
// BigInteger object to store result
BigInteger res[];
// For user input
// Use Scanner or BufferedReader
// Two object of String created
// Holds the values to perform operation
String input1 = "-9";
// Convert the string input to BigInteger
BigInteger a
= new BigInteger(input1);
// Using sqrtAndRemainder() method
try {
res = a.sqrtAndRemainder();
// Display the result
System.out.println("The square root of\n"
+ a + "\nis " + res[0]
+ "\nand remainder is "
+ res[1]);
}
catch (ArithmeticException e) {
System.out.println(e);
}
}
}
输出:
java.lang.ArithmeticException: Negative BigInteger
参考资料:https://docs . Oracle . com/javae/9/docs/API/Java/math/big integer . html # sqrtandemainder--
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