Java 中的 BigDecimal min()方法
原文:https://www . geesforgeks . org/big decimal-min-method-in-Java/
java 中的Java . math . BigDecimal . min(BigDecimal val)方法用于比较两个 BigDecimal 值，并返回这两个值的最小值。
语法:
public BigDecimal min(BigDecimal val)
参数:函数接受一个大十进制对象值作为参数，其值与该大十进制对象的值进行比较，并返回最小值。
返回值:该方法返回大十进制数，其值是这个大十进制数和值中较小的一个。如果两者相等，则返回这个大十进制。
例:
Input : a = 17.000041900, b = 17.0000418999
Output : 17.0000418999
Input : a = 235900000146, b = 236000000000
Output : 235900000146
下面的程序将说明 BigDecimal 类的 min()函数:
程序 1:
/*Java program to illustrate
use of BigDecimal min()
function in Java */
import java.math.*;
public class GFG {
public static void main(String[] args)
{
// Creating 2 BigDecimal objects
BigDecimal a, b;
a = new BigDecimal("17.000041900");
b = new BigDecimal("17.0000418999");
// print the maximum value
System.out.println("Minimum Value among " + a +
" and " + b + " is " + a.min(b));
}
}
输出:
Minimum Value among 17.000041900 and 17.0000418999 is 17.0000418999
程序二:
/*Java program to illustrate
use of BigDecimal min()
to display minimum length
among two strings */
import java.math.*;
public class GFG {
public static void main(String[] args)
{
// Create 2 BigDecimal objects
BigDecimal a, b;
String s = "GeeksforGeeks";
String str = "GeeksClasses";
int l1, l2;
l1 = s.length();
l2 = str.length();
a = new BigDecimal(l1);
b = new BigDecimal(l2);
// Print the respective lengths
System.out.println("Length of string " + s + " is " + a);
System.out.println("Length of string " + str + " is " + b);
// Print the maximum value
System.out.println("Minimum length is " + a.min(b));
}
}
输出:
Length of string GeeksforGeeks is 13
Length of string GeeksClasses is 12
Minimum length is 12
参考:https://docs . Oracle . com/javase/7/docs/API/Java/math/bigdecimal . html # min()
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