将给定数字的值放入数字中
位置值可以定义为数字中的一个数字根据其在数字中的位置所代表的值。以下是地点价值的示例说明:
我们再举一个例子来说明N = 45876T2 的位置值
问题: 给定一个正整数 N 和一个数字 D 。任务是找出一个数字 D 在给定数字 N 中的位置值。如果数字出现多次，则找到最小位置值。 例:
输入: N = 3928，D = 3 输出: 3000 说明: 此数中 3 的位置值为 31000 = 3000 输入: N = 67849，D = 6 输出:* 60000
解决方法:
- 从输入数字的右侧找到数字的位置。为了找到这个位置，把这个数的模除以 10，检查这个数，然后把这个数除以 10。
- 找到数字的位置后，将数字乘以 10 位置 。
下面是上述方法的实现:
C++
// C++ implementation to find
// place value of a number
#include<bits/stdc++.h>
using namespace std;
// Function to find place value
int placeValue(int N, int num)
{
int total = 1, value = 0, rem = 0;
while (true)
{
rem = N % 10;
N = N / 10;
if (rem == num)
{
value = total * rem;
break;
}
total = total * 10;
}
return value;
}
// Driver Code
int main()
{
// Digit, which we want
// to find place value.
int D = 5;
// Number from where we
// want to find place value.
int N = 85932;
cout << (placeValue(N, D));
}
// This code is contributed by Ritik Bansal
Java 语言(一种计算机语言，尤用于创建网站)
// Java implementation to find
// place value of a number
import java.util.*;
import java.io.*;
import java.lang.*;
class GFG {
// function to find place value
static int placeValue(int N, int num)
{
int total = 1, value = 0, rem = 0;
while (true) {
rem = N % 10;
N = N / 10;
if (rem == num) {
value = total * rem;
break;
}
total = total * 10;
}
return value;
}
// Driver Code
public static void main(String[] args)
{
// Digit, which we want
// to find place value.
int D = 5;
// Number from where we
// want to find place value.
int N = 85932;
System.out.println(placeValue(N, D));
}
}
Python 3
# Python3 implementation to find
# place value of a number
# Function to find place value
def placeValue(N, num):
total = 1
value = 0
rem = 0
while (True):
rem = N % 10
N = N // 10
if (rem == num):
value = total * rem
break
total = total * 10
return value
# Driver Code
# Digit, which we want
# to find place value.
D = 5
# Number from where we
# want to find place value.
N = 85932
print(placeValue(N, D))
# This code is contributed by divyamohan123
C
// C# implementation to find
// place value of a number
using System;
class GFG{
// function to find place value
static int placeValue(int N, int num)
{
int total = 1, value = 0, rem = 0;
while (true)
{
rem = N % 10;
N = N / 10;
if (rem == num)
{
value = total * rem;
break;
}
total = total * 10;
}
return value;
}
// Driver Code
public static void Main()
{
// Digit, which we want
// to find place value.
int D = 5;
// Number from where we
// want to find place value.
int N = 85932;
Console.Write(placeValue(N, D));
}
}
// This code is contributed by Code_Mech
java 描述语言
<script>
// JavaScript implementation to find
// place value of a number
// Function to find place value
function placeValue(N, num) {
var total = 1,
value = 0,
rem = 0;
while (true) {
rem = N % 10;
N = parseInt(N / 10);
if (rem == num) {
value = total * rem;
break;
}
total = total * 10;
}
return value;
}
// Driver Code
// Digit, which we want
// to find place value.
var D = 5;
// Number from where we
// want to find place value.
var N = 85932;
document.write(placeValue(N, D));
</script>
Output:
5000
时间复杂度: O(log N) 辅助空间: O(1)
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