最大偶数和奇数 N 位数

原文:https://www . geesforgeks . org/最大偶数和奇数 n 位数/

给定一个整数 N ,任务是找出最大的偶数和奇数 N 位数。 例:

输入: N = 4 输出: 偶数= 9998 奇数= 9999 输入: N = 2 输出: 偶数= 98 奇数= 99

进场:

  • 最大的 N 位偶数将是(10N)–2,因为 N 不同值的系列将是 8,98,998,9998,…..
  • 同样,最大的 N 位奇数将是(10N)–1系列 9,99,999,9999,…..

以下是上述方法的实现:

C++

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;

// Function to print the largest n-digit
// even and odd numbers
void findNumbers(int n)
{
    int odd = pow(10, n) - 1;
    int even = odd - 1;
    cout << "Even = " << even << endl;
    cout << "Odd = " << odd;
}

// Driver code
int main()
{
    int n = 4;
    findNumbers(n);

    return 0;
}

Java 语言(一种计算机语言,尤用于创建网站)

// Java implementation of the approach
class GFG {

    // Function to print the largest n-digit
    // even and odd numbers
    static void findNumbers(int n)
    {
        int odd = (int)Math.pow(10, n) - 1;
        int even = odd - 1;
        System.out.println("Even = " + even);
        System.out.print("Odd = " + odd);
    }

    // Driver code
    public static void main(String args[])
    {
        int n = 4;
        findNumbers(n);
    }
}

C

// C# implementation of the approach
using System;
class GFG {

    // Function to print the largest n-digit
    // even and odd numbers
    static void findNumbers(int n)
    {
        int odd = (int)Math.Pow(10, n) - 1;
        int even = odd - 1;
        Console.WriteLine("Even = " + even);
        Console.Write("Odd = " + odd);
    }

    // Driver code
    public static void Main()
    {
        int n = 4;
        findNumbers(n);
    }
}

Python 3

# Python3 implementation of the approach

# Function to print the largest n-digit
# even and odd numbers
def findNumbers(n):

    odd = pow(10, n) - 1
    even = odd - 1
    print("Even = ", even)
    print("Odd = ", odd)

# Driver code
n = 4
findNumbers(n)

# This code is contributed by ihritik

服务器端编程语言(Professional Hypertext Preprocessor 的缩写)

<?php
// PHP implementation of the approach

// Function to print the largest n-digit
// even and odd numbers
function findNumbers($n)
{
    $odd = pow(10, $n) - 1;
    $even = $odd - 1;
    echo "Even = $even \n";
    echo "Odd = $odd";
}

// Driver code
$n = 4 ;
findNumbers($n);

// This code is contributed by ihritik
?>

java 描述语言

<script>

   // Javascript implementation of the approach

   // Function to print the largest n-digit
   // even and odd numbers
   function findNumbers(n)
   {
       var odd = Math.pow(10, n) - 1;
       var even = odd - 1;
       document.write("Even = " + even+"<br>");
       document.write("Odd = " + odd);
   }

   // Driver code
   var n = 4;
   findNumbers(n);

   // This code is contributed by rrrtnx.
     </script>

Output: 

Even = 9998
Odd = 9999