从给定的根求二次方程

原文:https://www . geeksforgeeks . org/从给定的根中找到二次方程/

给定一个二次方程 A 和 B 的根，任务是找到方程。 注:给定的根是整数。

示例:

输入: A = 2，B = 3 输出:x^2 –( 5x)+(6)= 0 x²–5x+6 = 0 x²-3x-2x+6 = 0 x(x–3)–2(x–3)= 0 (x–3)(x–2)= 0 x = 2，3

输入: A = 5，B = 10 输出:x^2 –( 15x)+(50)= 0

逼近:如果一个二次方程 ax ² + bx + c = 0 的根是 A 和 B ，那么已知 T11】A+B =–B/A 和 A * B = c * a 。 现在，ax ² + bx + c = 0 可以写成 x²+(b/a)x+(c/a)= 0(自，a！= 0) x²–(A+B)x +(A * B)= 0、【自，A + B = -b * a 和 A * B = c * A】 即x²–(根之和)x+根之积= 0

下面是上述方法的实现:

C++

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;

// Function to find the quadratic
// equation whose roots are a and b
void findEquation(int a, int b)
{
    int sum = (a + b);
    int product = (a * b);
    cout << "x^2 - (" << sum << "x) + ("
         << product << ") = 0";
}

// Driver code
int main()
{
    int a = 2, b = 3;

    findEquation(a, b);

    return 0;
}

Java 语言(一种计算机语言，尤用于创建网站)

// Java implementation of the above approach
class GFG
{

    // Function to find the quadratic
    // equation whose roots are a and b
    static void findEquation(int a, int b)
    {
        int sum = (a + b);
        int product = (a * b);
        System.out.println("x^2 - (" + sum +
                           "x) + (" + product + ") = 0");
    }

    // Driver code
    public static void main(String args[])
    {
        int a = 2, b = 3;

        findEquation(a, b);
    }
}

// This code is contributed by AnkitRai01

Python 3

# Python3 implementation of the approach

# Function to find the quadratic
# equation whose roots are a and b
def findEquation(a, b):
    summ = (a + b)
    product = (a * b)
    print("x^2 - (", summ,
          "x) + (", product, ") = 0")

# Driver code
a = 2
b = 3

findEquation(a, b)

# This code is contributed by Mohit Kumar

C

// C# implementation of the above approach
using System;
class GFG
{

    // Function to find the quadratic
    // equation whose roots are a and b
    static void findEquation(int a, int b)
    {
        int sum = (a + b);
        int product = (a * b);
        Console.WriteLine("x^2 - (" + sum +
                          "x) + (" + product + ") = 0");
    }

    // Driver code
    public static void Main()
    {
        int a = 2, b = 3;

        findEquation(a, b);
    }
}

// This code is contributed by CodeMech.

java 描述语言

<script>

// Javascript implementation of the above approach

// Function to find the quadratic
// equation whose roots are a and b
function findEquation(a, b)
{
    var sum = (a + b);
    var product = (a * b);
    document.write("x^2 - (" + sum +
                    "x) + (" + product +
                    ") = 0");
}

// Driver Code
var a = 2, b = 3;

findEquation(a, b);

// This code is contributed by Ankita saini

</script>

Output: 

x^2 - (5x) + (6) = 0

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