求数列 1+11+111+1111+的和…..最新条款
原文:https://www . geesforgeks . org/find-sum-series-111111111-upto-n-terms/
这里我们要求数列 1 + 11 + 111 + 1111 +的和…..最多 N 个术语(其中 N 是给定的)。 例:
Input : 3
Output : 1 + 11 + 111 +....
Total sum is : 123
Input : 4
Output : 1 + 11 + 111 + 1111 +.....
Total sum is : 1234
Input : 7
Output : 1 + 11 + 111 + 1111 + 11111 +
111111 + 1111111 +.....
Total sum is : 1234567
这里我们看到，当 N 的值为 3 时，级数持续到 1 + 11 + 111，即三项，其和为 123。 求上述级数和的程序:
C++
// C++ program to find the sum of
// the series 1+11+111+1111+....
#include <bits/stdc++.h>
using namespace std;
// Function for finding summation
int summation(int n)
{
int sum = 0, j = 1;
for (int i = 1; i <= n; i++) {
sum = sum + j;
// Appending a 1 at the end
j = (j * 10) + 1;
}
return sum;
}
// Driver Code
int main()
{
int n = 5;
cout << " " << summation(n);
return 0;
}
// This code is contributed by shivanisinghss2110
C
// C program to find the sum of
// the series 1+11+111+1111+....
#include <stdio.h>
// Function for finding summation
int summation(int n)
{
int sum = 0, j = 1;
for (int i = 1; i <= n; i++) {
sum = sum + j;
// Appending a 1 at the end
j = (j * 10) + 1;
}
return sum;
}
// Driver Code
int main()
{
int n = 5;
printf("%d", summation(n));
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to find the sum of
// the series 1+11+111+1111+....
import java.io.*;
class GFG
{
// Function for finding summation
static int summation(int n)
{
int sum = 0, j = 1;
for (int i = 1; i <= n; i++)
{
sum = sum + j;
j = (j * 10) + 1;
}
return sum;
}
// Driver Code
public static void main(String args[])
{
int n = 5;
System.out.println(summation(n));
}
}
// This code is contributed
// by Nikita Tiwari
计算机编程语言
# Python program to get the summation
# of following series
def summation(n):
sum = 0
j = 1
for i in range(1, n + 1):
sum = sum + j
j = (j * 10) + 1
return sum
# Driver Code
n = 5
print(summation(n))
C
// C# program to find the sum of
// the series 1+11+111+1111+....
using System;
class GFG
{
// Function for finding summation
static int summation(int n)
{
int sum = 0, j = 1;
for (int i = 1; i <= n; i++)
{
sum = sum + j;
j = (j * 10) + 1;
}
return sum;
}
// Driver Code
public static void Main()
{
int n = 5;
Console.WriteLine(summation(n));
}
}
// This code is contributed by vt_m
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to find the sum of
// the series 1+11+111+1111+....
// Function for finding summation
function summation($n)
{
$sum = 0; $j = 1;
for ($i = 1; $i <= $n; $i++)
{
$sum = $sum + $j;
// Appending a 1 at the end
$j = ($j * 10) + 1;
}
return $sum;
}
// Driver Code
$n = 5;
echo summation($n);
// This code is contributed by ajit
?>
java 描述语言
<script>
// Javascript program to find the sum of
// the series 1+11+111+1111+....
// Function for finding summation
function summation( n) {
let sum = 0, j = 1;
for ( let i = 1; i <= n; i++) {
sum = sum + j;
// Appending a 1 at the end
j = (j * 10) + 1;
}
return sum;
}
// Driver Code
let n = 5;
document.write(summation(n));
// This code contributed by Princi Singh
</script>
输出:
12345
另一种方法:让给定的数列 S = 1 + 11 + 111 + 1111 +。。。+直到第 n 个学期。用公式求数列的和。
下面是上述方法的实现。
C++
// C++ program to find the sum of
// the series 1+11+111+1111+....
#include <bits/stdc++.h>
// Function for finding summation
int summation(int n)
{
int sum;
sum = (pow(10, n + 1) -
10 - (9 * n)) / 81;
return sum;
}
// Driver Code
int main()
{
int n = 5;
printf("%d", summation(n));
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// java program to find the sum of
// the series 1+11+111+1111+....
import java.io.*;
class GFG {
// Function for finding summation
static int summation(int n)
{
int sum;
sum = (int)(Math.pow(10, n + 1) -
10 - (9 * n)) / 81;
return sum;
}
// Driver Code
public static void main (String[] args)
{
int n = 5;
System.out.println(summation(n));
}
}
// This code is contributed by anuj_67.
Python 3
# Python3 program to
# find the sum of
# the series 1+11+111+1111+....
import math
# Function for
# finding summation
def summation(n):
return int((pow(10, n + 1) -
10 - (9 * n)) / 81);
# Driver Code
print(summation(5));
# This code is contributed
# by mits.
C
// C# program to find the sum of
// the series 1+11+111+1111+....
using System;
class GFG {
// Function for finding summation
static int summation(int n)
{
int sum;
sum = (int)(Math.Pow(10, n + 1) -
10 - (9 * n)) / 81;
return sum;
}
// Driver Code
public static void Main ()
{
int n = 5;
Console.WriteLine(summation(n));
}
}
// This code is contributed by anuj_67.
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
//PHP program to find the sum of
// the series 1+11+111+1111+....
// Function for finding summation
function summation($n)
{
$sum;
$sum = (pow(10, $n + 1) -
10 - (9 * $n)) / 81;
return $sum;
}
// Driver Code
$n = 5;
echo summation($n);
// This code is contributed by aj_36
?>
java 描述语言
<script>
// javascript program to find the sum of
// the series 1+11+111+1111+....
// Function for finding summation
function summation( n)
{
let sum;
sum = (Math.pow(10, n + 1) -
10 - (9 * n)) / 81;
return sum;
}
// Driver Code
let n = 5;
document.write(summation(n)) ;
// This code is contributed by aashish1995
</script>
输出:
12345
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