找出包含数字 d 的数字
原文:https://www.geeksforgeeks.org/find-number-contain-digit-d/
给定两个整数 n 和 d，任务是找出 0 到 n 之间包含特定数字 d 的数字
示例:
Input : n = 20
d = 5
Output : 5 15
Input : n = 50
d = 2
Output : 2 12 20 21 22 23 24 25 26 27 28 29 32 42
方法 1: 从 0 到 n 做一个循环，逐一检查每个数字，如果数字包含数字 d，则打印出来，否则增加数字。继续这个过程，直到循环结束。
C++
// C++ program to print the number which
// contain the digit d from 0 to n
#include <bits/stdc++.h>
using namespace std;
// Returns true if d is present as digit
// in number x.
bool isDigitPresent(int x, int d)
{
// Breal loop if d is present as digit
while (x > 0)
{
if (x % 10 == d)
break;
x = x / 10;
}
// If loop broke
return (x > 0);
}
// function to display the values
void printNumbers(int n, int d)
{
// Check all numbers one by one
for (int i = 0; i <= n; i++)
// checking for digit
if (i == d || isDigitPresent(i, d))
cout << i << " ";
}
// Driver code
int main()
{
int n = 47, d = 7;
printNumbers(n, d);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to print the number which
// contain the digit d from 0 to n
class GFG
{
// Returns true if d is present as digit
// in number x.
static boolean isDigitPresent(int x, int d)
{
// Breal loop if d is present as digit
while (x > 0)
{
if (x % 10 == d)
break;
x = x / 10;
}
// If loop broke
return (x > 0);
}
// function to display the values
static void printNumbers(int n, int d)
{
// Check all numbers one by one
for (int i = 0; i <= n; i++)
// checking for digit
if (i == d || isDigitPresent(i, d))
System.out.print(i + " ");
}
// Driver code
public static void main(String[] args)
{
int n = 47, d = 7;
printNumbers(n, d);
}
}
Python 3
# Python3 program to print the number which
# contain the digit d from 0 to n
# Returns true if d is present as digit
# in number x.
def isDigitPresent(x, d):
# Breal loop if d is present as digit
while (x > 0):
if (x % 10 == d):
break
x = x / 10
# If loop broke
return (x > 0)
# function to display the values
def printNumbers(n, d):
# Check all numbers one by one
for i in range(0, n+1):
# checking for digit
if (i == d or isDigitPresent(i, d)):
print(i,end=" ")
# Driver code
n = 47
d = 7
print("The number of values are")
printNumbers(n, d)
#This code is contributed by
#Smitha Dinesh Semwal
C
// C# program to print the number which
// contain the digit d from 0 to n
using System;
class GFG {
// Returns true if d is present as digit
// in number x.
static bool isDigitPresent(int x, int d)
{
// Breal loop if d is present as digit
while (x > 0)
{
if (x % 10 == d)
break;
x = x / 10;
}
// If loop broke
return (x > 0);
}
// function to display the values
static void printNumbers(int n, int d)
{
// Check all numbers one by one
for (int i = 0; i <= n; i++)
// checking for digit
if (i == d || isDigitPresent(i, d))
Console.Write(i + " ");
}
// Driver code
public static void Main()
{
int n = 47, d = 7;
printNumbers(n, d);
}
}
// This code contribute by parashar.
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to print the number which
// contain the digit d from 0 to n
// Returns true if d is present as digit
// in number x.
function isDigitPresent($x, $d)
{
// Breal loop if d is
// present as digit
while ($x > 0)
{
if ($x % 10 == $d)
break;
$x = $x / 10;
}
// If loop broke
return ($x > 0);
}
// function to display the values
function printNumbers($n, $d)
{
// Check all numbers one by one
for ($i = 0; $i <= $n; $i++)
// checking for digit
if ($i == $d || isDigitPresent($i, $d))
echo $i , " ";
}
// Driver Code
$n = 47;
$d = 7;
printNumbers($n, $d);
// This code contributed by ajit.
?>
java 描述语言
<script>
// JavaScript program to print the number which
// contain the digit d from 0 to n
// Returns true if d is present as digit
// in number x.
function isDigitPresent(x, d)
{
// Breal loop if d is present as digit
while (x > 0)
{
if (x % 10 == d)
break;
x = x / 10;
}
// If loop broke
return (x > 0);
}
// Function to display the values
function printNumbers(n, d)
{
// Check all numbers one by one
for(let i = 0; i <= n; i++)
// Checking for digit
if (i == d || isDigitPresent(i, d))
document.write(i + " ");
}
// Driver code
let n = 47, d = 7;
printNumbers(n, d);
// This code is contributed by splevel62
</script>
Output:
The number of values are
7 17 27 37 47
方法 2: 这种方法使用每个数字作为字符串，并检查数字是否存在。这种方法使用 String.indexOf()函数来检查字符串中是否存在该字符。 String.indexOf() > = 0 表示存在字符 ，String.indexOf() = -1 表示不存在字符
C++
// CPP program to print the number which
// contain the digit d from 0 to n
#include<bits/stdc++.h>
using namespace std;
// function to display the values
void printNumbers(int n, int d)
{
// Converting d to character
string st = "";
st += to_string(d);
char ch = st[0];
string p = "";
p += ch;
// Loop to check each digit one by one.
for (int i = 0; i <= n; i++)
{
// initialize the string
st = "";
st = st + to_string(i);
int idx = st.find(p);
// checking for digit
if (i == d || idx!=-1)
cout << (i) << " ";
}
}
// Driver code
int main()
{
int n = 100, d = 5;
printNumbers(n, d);
}
// This code is contributed by
// Surendra_Gangwar
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to print the number which
// contain the digit d from 0 to n
public class GFG {
// function to display the values
static void printNumbers(int n, int d)
{
// Converting d to character
String st = "" + d;
char ch = st.charAt(0);
// Loop to check each digit one by one.
for (int i = 0; i <= n; i++) {
// initialize the string
st = "";
st = st + i;
// checking for digit
if (i == d || st.indexOf(ch) >= 0)
System.out.print(i + " ");
}
}
// Driver code
public static void main(String[] args)
{
int n = 100, d = 5;
printNumbers(n, d);
}
}
Python 3
# Python 3 program to print the number
# which contain the digit d from 0 to n
def index(st, ch):
for i in range(len(st)):
if(st[i] == ch):
return i;
return -1
# function to display the values
def printNumbers(n, d):
# Converting d to character
st = "" + str(d)
ch = st[0]
# Loop to check each digit one by one.
for i in range(0, n + 1, 1):
# initialize the string
st = ""
st = st + str(i)
# checking for digit
if (i == d or index(st, ch) >= 0):
print(i, end = " ")
# Driver code
if __name__ == '__main__':
n = 100
d = 5
printNumbers(n, d)
# This code is contributed by
# Shashank_Sharma
C
// C# program to print the number which
// contain the digit d from 0 to n
using System;
class GFG
{
// function to display the values
static void printNumbers(int n, int d)
{
// Converting d to character
String st = "" + d;
char ch = st[0];
// Loop to check each digit one by one.
for (int i = 0; i < n; i++)
{
// initialize the string
st = "";
st = st + i;
// checking for digit
if (i == d || st.IndexOf(ch) >= 0)
Console.Write(i + " ");
}
}
// Driver code
public static void Main()
{
int n = 100, d = 5;
printNumbers(n, d);
}
}
/* This code contributed by PrinciRaj1992 */
java 描述语言
<script>
// Javascript program to print the number which
// contain the digit d from 0 to n
// Function to display the values
function printNumbers(n, d)
{
// Converting d to character
let st = "" + d;
let ch = st[0];
// Loop to check each digit one by one.
for(let i = 0; i < n; i++)
{
// Initialize the string
st = "";
st = st + i;
// Checking for digit
if (i == d || st.indexOf(ch) >= 0)
document.write(i + " ");
}
}
// Driver code
let n = 100, d = 5;
printNumbers(n, d);
// This code is contributed by decode2207
</script>
Output:
5 15 25 35 45 50 51 52 53 54 55 56 57 58 59 65 75 85 95
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