当给出(A + B)、(A + C)和(B + C)中的两个时，求 A、B 和 C 的最小可能值

原文:https://www . geeksforgeeks . org/find-a-b-a-c 和 b-c-b-c-中的两个给定时 a-b-b-c 和 c-c-的最小可能值/

给定两个整数 X 和 Y 。 X 和 Y 代表(A + B)、(A + C)和(B + C)中的任意两个值。任务是找到 A 、 B 和 C ，使得 A + B + C 最小可能。 举例:

输入: X = 3，Y = 4 T3】输出: 2 1 2 A = 2，B = 1，C = 2。 那么 A + B = 3，A + C = 4。 A + B + C = 5，这是最小可能值。 输入: X = 123，Y = 13 输出: 1 12 111

进场:让X = A+BY = B+C。如果 X > Y 让我们交换一下。注意A+b+ C = A+b+(Y–B)= A+Y。这就是为什么最小化 A 的值是最佳的。所以 A 的值可以一直是 1 。然后B = X–A和C = Y–B。 以下是上述办法的实施:

C++

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;

// Function to find A, B and C
void MinimumValue(int x, int y)
{

    // Keep minimum number in x
    if (x > y)
        swap(x, y);

    // Find the numbers
    int a = 1;
    int b = x - 1;
    int c = y - b;

    cout << a << " " << b << " " << c;
}

// Driver code
int main()
{
    int x = 123, y = 13;

    // Function call
    MinimumValue(x, y);

    return 0;
}

Java 语言(一种计算机语言，尤用于创建网站)

// Java implementation of the approach
import java.io.*;

class GFG
{

// Function to find A, B and C
static void MinimumValue(int x, int y)
{

    // Keep minimum number in x
    if (x > y)
    {
        int temp = x;
            x = y;
            y = temp;
    }

    // Find the numbers
    int a = 1;
    int b = x - 1;
    int c = y - b;

    System.out.print( a + " " + b + " " + c);
}

// Driver code
public static void main (String[] args)
{
    int x = 123, y = 13;

    // Function call
    MinimumValue(x, y);
}
}

// This code is contributed by anuj_67..

Python 3

# Python3 implementation of the approach

# Function to find A, B and C
def MinimumValue(x, y):

    # Keep minimum number in x
    if (x > y):
        x, y = y, x

    # Find the numbers
    a = 1
    b = x - 1
    c = y - b

    print(a, b, c)

# Driver code
x = 123
y = 13

# Function call
MinimumValue(x, y)

# This code is contributed by Mohit Kumar

C

// C# implementation of the approach
using System;

class GFG
{

// Function to find A, B and C
static void MinimumValue(int x, int y)
{

    // Keep minimum number in x
    if (x > y)
    {
        int temp = x;
            x = y;
            y = temp;
    }

    // Find the numbers
    int a = 1;
    int b = x - 1;
    int c = y - b;

    Console.WriteLine( a + " " + b + " " + c);
}

// Driver code
public static void Main ()
{
    int x = 123, y = 13;

    // Function call
    MinimumValue(x, y);
}
}

// This code is contributed by anuj_67..

java 描述语言

<script>
// javascript implementation of the approach

// Function to find A, B and C
function MinimumValue(x, y)
{

    // Keep minimum number in x
    if (x > y)
    {
        var temp = x;
            x = y;
            y = temp;
    }

    // Find the numbers
    var a = 1;
    var b = x - 1;
    var c = y - b;

    document.write( a + " " + b + " " + c);
}

// Driver code
    var x = 123, y = 13;

    // Function call
    MinimumValue(x, y);

// This code is contributed by Amit Katiyar

</script>

Output: 

1 12 111

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