带示例的 Java 中的 OffsetDateTime withHour()方法

原文:https://www . geeksforgeeks . org/offsetdatetime-with our-method-in-Java-with-examples/

Java 中 OffsetDateTime 类的withour()方法返回该 OffsetDateTime 的副本,并按照参数中的指定更改一天中的小时。

语法:

public OffsetDateTime withHour(int hour)

参数:该方法接受单个参数小时,该参数指定要在结果中设置的一天中的小时,范围从 0 到 23。

返回值:返回基于该日期的偏置日期时间,请求一天中的小时,不为空。

异常:当一天中的小时值无效或一年中的某一天无效时,程序会抛出日期时间异常

下面的程序说明了的方法:

程序 1:

// Java program to demonstrate the withHour() method

import java.time.OffsetDateTime;
import java.time.ZonedDateTime;

public class GFG {
    public static void main(String[] args)
    {

        // Parses the date1
        OffsetDateTime date1
            = OffsetDateTime
                  .parse(
                      "2018-12-12T13:30:30+05:00");

        // Prints dates
        System.out.println("Date1: " + date1);

        // Changes the hour of day
        System.out.println("Date1 after altering hour of the day: "
                           + date1.withHour(20));
    }
}

输出:

Date1: 2018-12-12T13:30:30+05:00
Date1 after altering hour of the day: 2018-12-12T20:30:30+05:00

程序二:

// Java program to demonstrate the withHour() method

import java.time.OffsetDateTime;

public class GFG {
    public static void main(String[] args)
    {
        try {
            // Parses the date1
            OffsetDateTime date1
                = OffsetDateTime
                      .parse(
                          "2018-12-12T13:30:30+05:00");

            // Prints dates
            System.out.println("Date1: " + date1);

            // Changes the hour of day
            System.out.println("Date1 after altering hour of the day: "
                               + date1.withHour(27));
        }
        catch (Exception e) {
            System.out.println("Exception: " + e);
        }
    }
}

输出:

Date1: 2018-12-12T13:30:30+05:00
Exception: java.time.DateTimeException:
           Invalid value for HourOfDay (valid values 0 - 23): 27

参考:https://docs . Oracle . com/javase/10/docs/API/Java/time/offsetdatetime . html # withour(int)