JavaTuples 中的十年类

原文:https://www.geeksforgeeks.org/decade-class-in-java-tuples/

一个十年是一个来自 JavaTuples 库的元组，处理 3 个元素。因为这个十年是一个泛型类，所以它可以包含任何类型的值。 由于十年是一个元组，因此它也具有 JavaTuples 的所有特征:

  • 它们是型安全
  • 它们是不可改变的
  • 它们是可重复的
  • 它们是可序列化的
  • 它们是可比的(实现可比的<元组>
  • 它们实现了等于()和哈希码()
  • 它们还实现了 toString()

类别声明

public final class Decade<A, B, C, D, E, F, G, H, I, J>
extends Tuple
implements IValue0<A>, IValue1<B>, IValue2<C>, IValue3<D>, IValue4<E>, 
           IValue5<F, IValue6<G, IValue7<H>, IValue8<I, J>

类层次

Object
  ↳ org.javatuples.Tuple
      ↳ org.javatuples.Decade<A, B, C, D, E, F, G, H, I, J>

创建十年元组

  • 从构造器: T3】语法 :
Decade<A, B, C, D, E, F, G, H, I, J> decade = 
    new Decade<A, B, C, D, E, F, G, H, I, J>
        (value1, value2, value3, value4, value5, value6, value7, value8, value9, value10);
  • 例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to create
// a Decade tuple from Constructor

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                            Integer, Integer, Integer> decade
            = Decade.with(Integer.valueOf(1),
                        Integer.valueOf(2),
                        Integer.valueOf(3),
                        Integer.valueOf(4),
                        Integer.valueOf(5),
                        Integer.valueOf(6),
                        Integer.valueOf(7),
                        Integer.valueOf(8),
                        Integer.valueOf(9),
                        Integer.valueOf(10));

        System.out.println(decade);
    }
}
  • 输出:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
  • 使用 with()方法:with()方法是 JavaTuples 库提供的一个函数，用这样的值来实例化对象。 语法 :
Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    Decade.with(value1, value2, value3, value4, value5, value6, value7, value8, value9, value10);
  • 例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to create
// a Decade tuple from with() method

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                                               Integer, Integer> decade
            = Decade.with(Integer.valueOf(1),
                          Integer.valueOf(2),
                          Integer.valueOf(3),
                          Integer.valueOf(4),
                          Integer.valueOf(5),
                          Integer.valueOf(6),
                          Integer.valueOf(7),
                          Integer.valueOf(8),
                          Integer.valueOf(9),
                          Integer.valueOf(10));

        System.out.println(decade);
    }
}
  • 输出:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
  • 来自其他集合:From collection()方法用于从集合创建 Tuple，fromArray()方法用于从数组创建。集合/数组的类型必须与元组的类型相同，并且集合/数组中的值的数量必须与元组类匹配。 语法 :
Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    Decade.fromCollection(collectionWith_10_value);

Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    Decade.fromArray(arrayWith_10_value);
  • 例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to create
// a Decade tuple from Collection

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        // Creating Decade from List
        List<Integer> list = new ArrayList<Integer>();
        list.add(1);
        list.add(2);
        list.add(3);
        list.add(4);
        list.add(5);
        list.add(6);
        list.add(7);
        list.add(8);
        list.add(9);
        list.add(10);

        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                              Integer, Integer, Integer> decade
            = Decade.fromCollection(list);

        // Creating Decade from Array
        Integer[] arr = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };

        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                           Integer, Integer, Integer> otherDecade
            = Decade.fromArray(arr);

        System.out.println(decade);
        System.out.println(otherDecade);
    }
}
  • 输出:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

获取价值

getValueX()方法可用于在索引 x 处获取元组中的值。元组中的索引从 0 开始。因此，索引 X 处的值代表位置 X+1 处的值。 语法 :

Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    new Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9>
        (value1, value2, value3, value4, value5, value6, value7, value8, value9, value10);

type1 val1 = decade.getValue0();

例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to get
// a Decade value

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                               Integer, Integer, Integer> decade
            = Decade.with(Integer.valueOf(1),
                          Integer.valueOf(2),
                          Integer.valueOf(3),
                          Integer.valueOf(4),
                          Integer.valueOf(5),
                          Integer.valueOf(6),
                          Integer.valueOf(7),
                          Integer.valueOf(8),
                          Integer.valueOf(9),
                          Integer.valueOf(10));

        System.out.println(decade.getValue0());
        System.out.println(decade.getValue2());
    }
}

输出:

1
3

设置十进制值

由于元组是不可变的，这意味着在任何索引处修改值都是不可能的。 因此 JavaTuples 提供 setAtX(value) ，它在索引 X 处创建一个具有新值的元组的副本，并返回该元组。 语法 :

Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    new Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9>
                (value1, value2, value3, value4, value5, value6, value7, value8, value9, value10);

Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> 
    otherDecade = decade.setAtX(value);

例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to set
// a Decade value

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                               Integer, Integer, Integer> decade
            = Decade.with(Integer.valueOf(1),
                          Integer.valueOf(2),
                          Integer.valueOf(3),
                          Integer.valueOf(4),
                          Integer.valueOf(5),
                          Integer.valueOf(6),
                          Integer.valueOf(7),
                          Integer.valueOf(8),
                          Integer.valueOf(9),
                          Integer.valueOf(10));

        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                            Integer, Integer, Integer> otherDecade
            = decade.setAt3(40);

        System.out.println(otherDecade);
    }
}

输出:

[1, 2, 3, 40, 5, 6, 7, 8, 9, 10]

添加值

JavaTuples 不支持超过 10 个值的元组。因此没有在十进制中增加值的功能。

十年寻找

可以使用预定义的方法在元组中搜索元素，该方法包含()。无论该值是否存在，它都会返回一个布尔值。 语法 :

Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    new Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9>
        (value1, value2, value3, value4, value5, value6, value7, value8, value9, value10);

boolean res = decade.contains(value2);

例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to search
// a value in a Decade

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                             Integer, Integer, Integer> decade
            = Decade.with(Integer.valueOf(1),
                          Integer.valueOf(2),
                          Integer.valueOf(3),
                          Integer.valueOf(4),
                          Integer.valueOf(5),
                          Integer.valueOf(6),
                          Integer.valueOf(7),
                          Integer.valueOf(8),
                          Integer.valueOf(9),
                          Integer.valueOf(10));

        boolean exist = decade.contains(5);
        boolean exist1 = decade.contains(false);

        System.out.println(exist);
        System.out.println(exist1);
    }
}

输出:

true
false

十年迭代

十年以来实现可迭代<对象>T1】界面。这意味着它们可以像集合或数组一样迭代。 语法 : 

Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9> decade = 
    new Decade<type1, type2, type3, type4, type5, type6, type7, type8, type9>
            (value1, value2, value3, value4, value5, value6, value7, value8, value9, value10);

for (Object item : decade) {
        ...
}

例 :

Java 语言(一种计算机语言，尤用于创建网站)

// Below is a Java program to iterate
// a Decade

import java.util.*;
import org.javatuples.Decade;

class GfG {
    public static void main(String[] args)
    {
        Decade<Integer, Integer, Integer, Integer, Integer, Integer, Integer,
                                               Integer, Integer, Integer> decade
            = Decade.with(Integer.valueOf(1),
                          Integer.valueOf(2),
                          Integer.valueOf(3),
                          Integer.valueOf(4),
                          Integer.valueOf(5),
                          Integer.valueOf(6),
                          Integer.valueOf(7),
                          Integer.valueOf(8),
                          Integer.valueOf(9),
                          Integer.valueOf(10));

        for (Object item : decade)
            System.out.println(item);
    }
}

输出:

1
2
3
4
5
6
7
8
9
10

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