查找一年中每天发生的次数
给一年时间。你的任务是找出一年中每天的数字，即该年中周一、周二、周三、周四、周五、周六、周日的数字。 例:
Input: 2019
Output: Monday-52
Tuesday-53
Wednesday-52
Thursday-52
Friday-52
Saturday-52
Sunday-52
Input: 2024
Output: Monday-53
Tuesday-53
Wednesday-52
Thursday-52
Friday-52
Saturday-52
Sunday-52
观察:我们要做一些关键的观察。第一个是一年中至少有 52 周，所以一年中每天至少发生 52 次。由于 527 等于 364，因此任何一年的 1 月 1 日这一天将出现 53 次，如果这一年是闰年，那么 1 月 2 日这一天也将出现 53 次。 方法:*创建一个列表，大小为 7，初始值为 52，最小出现次数为 52。找到第一天的索引。计算发生的天数为 53 天。 下面是实现。
Python 3
# python program Find number of
# times every day occurs in a Year
import datetime
import calendar
def day_occur_time(year):
# stores days in a week
days = [ "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday",
"Sunday" ]
# Initialize all counts as 52
L = [52 for i in range(7)]
# Find the index of the first day
# of the year
pos = -1
day = datetime.datetime(year, month = 1, day = 1).strftime("%A")
for i in range(7):
if day == days[i]:
pos = i
# mark the occurrence to be 53 of 1st day
# and 2nd day if the year is leap year
if calendar.isleap(year):
L[pos] += 1
L[(pos+1)%7] += 1
else:
L[pos] += 1
# Print the days
for i in range(7):
print(days[i], L[i])
# Driver Code
year = 2019
day_occur_time(year)
输出:
Monday 52
Tuesday 52
Wednesday 52
Thursday 52
Friday 53
Saturday 53
Sunday 52
版权属于：月萌API www.moonapi.com，转载请注明出处
