在矩阵中以加号“+”模式打印字符串
原文:https://www . geesforgeks . org/printing-string-plus-pattern-matrix/
给定一个字符串，在矩阵中打印出来，这样就形成了一个加号。
示例:
Input: TOP
Output:
X T X
T O P
X P X
Input: FEVER
Output:
X X F X X
X X E X X
F E V E R
X X E X X
X X R X X
进场: 思路很简单。首先，我们可以访问矩阵的每个元素，并使其为“X”。然后我们将在矩阵的中间行和中间列插入字符串的字符。例如，我们有一个长度为 5 的字符串。所以我们需要一个(5X5)矩阵。
为了访问矩阵的中间列，列索引被设为常数，并等于(n/2)，其中 n 是字符串的长度。它的行索引将从 0 变为(n-1)。 要访问中间行，行索引将被设为常量并等于(n/2)，列索引将从 0 变为(n-1)。
下面是上述方法的实现:
C++
// CPP program to print the
// string in 'plus' pattern
#include <bits/stdc++.h>
#define max 100
using namespace std;
// Function to make a cross in the matrix
void carveCross(string str)
{
int n = str.length();
if (n % 2 == 0)
{
/* As, it is not possible to make
the cross exactly in the middle of
the matrix with an even length string.*/
cout << "Not possible. Please enter "
<< "odd length string.\n";
}
else {
// declaring a 2D array i.e a matrix
char arr[max][max];
int m = n / 2;
/* Now, we will fill all the
elements of the array with 'X'*/
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
arr[i][j] = 'X';
}
}
/* Now, we will place the characters
of the string in the matrix, such
that a cross is formed in it.*/
for (int i = 0; i < n; i++)
{
/* here the characters of the
string will be added in the
middle column of our array.*/
arr[i][m] = str[i];
}
for (int i = 0; i < n; i++)
{
// here the characters of the
// string will be added in the
// middle row of our array.
arr[m][i] = str[i];
}
/* Now finally, we will print
the array*/
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
cout << arr[i][j] << " ";
}
cout << "\n";
}
}
}
// driver code
int main()
{
string str = "PICTURE";
carveCross(str);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to print the
// string in 'plus' pattern
class GFG {
static final int max = 100;
// Function to make a cross in the matrix
static void carveCross(String str) {
int n = str.length();
if (n % 2 == 0) {
// As, it is not possible to make
// the cross exactly in the middle of
// the matrix with an even length string.
System.out.print("Not possible. Please enter "
+ "odd length string.\n");
}
else {
// declaring a 2D array i.e a matrix
char arr[][] = new char[max][max];
int m = n / 2;
// Now, we will fill all the
// elements of the array with 'X'
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
arr[i][j] = 'X';
}
}
// Now, we will place the characters
// of the string in the matrix, such
// that a cross is formed in it.
for (int i = 0; i < n; i++) {
// here the characters of the
// string will be added in the
// middle column of our array.
arr[i][m] = str.charAt(i);
}
for (int i = 0; i < n; i++) {
// here the characters of the
// string will be added in the
// middle row of our array.
arr[m][i] = str.charAt(i);
}
// Now finally, we will print
// the array
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
System.out.print(arr[i][j] + " ");
}
System.out.print("\n");
}
}
}
// Driver code
public static void main(String[] args) {
String str = "PICTURE";
carveCross(str);
}
}
// This code is contributed by Anant Agarwal.
Python 3
# Python 3 program to print the
# string in 'plus' pattern
max = 100
# Function to make a cross
# in the matrix
def carveCross(str):
n = len(str)
if (n % 2 == 0) :
''' As, it is not possible to make
the cross exactly in the middle of
the matrix with an even length string.'''
print("Not possible. Please enter "
, "odd length string.\n")
else :
# declaring a 2D array i.e a matrix
arr = [[ False for x in range(max)]
for y in range(max)]
m = n // 2
''' Now, we will fill all the
elements of the array with 'X'''
for i in range( n) :
for j in range(n) :
arr[i][j] = 'X'
'''Now, we will place the characters
of the string in the matrix, such
that a cross is formed in it.'''
for i in range(n):
''' here the characters of the
string will be added in the
middle column of our array.'''
arr[i][m] = str[i]
for i in range(n):
# here the characters of the
# string will be added in the
# middle row of our array.
arr[m][i] = str[i]
# Now finally, we will print
# the array
for i in range(n):
for j in range(n):
print( arr[i][j] , end=" ")
print()
# Driver Code
if __name__ == "__main__":
str = "PICTURE"
carveCross(str)
# This code is contributed
# by ChitraNayal
C
// C# program to print the
// string in 'plus' pattern
using System;
class GFG {
static int max = 100;
// Function to make a cross in the matrix
static void carveCross(String str) {
int n = str.Length;
if (n % 2 == 0) {
// As, it is not possible to make
// the cross exactly in the middle of
// the matrix with an even length string.
Console.Write("Not possible. Please enter "
+ "odd length string.");
}
else {
// declaring a 2D array i.e a matrix
char [,]arr = new char[max,max];
int m = n / 2;
// Now, we will fill all the
// elements of the array with 'X'
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
arr[i,j] = 'X';
}
}
// Now, we will place the characters
// of the string in the matrix, such
// that a cross is formed in it.
for (int i = 0; i < n; i++) {
// here the characters of the
// string will be added in the
// middle column of our array.
arr[i,m] = str[i];
}
for (int i = 0; i < n; i++) {
// here the characters of the
// string will be added in the
// middle row of our array.
arr[m,i] = str[i];
}
// Now finally, we will print
// the array
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
Console.Write(arr[i,j] + " ");
}
Console.WriteLine();
}
}
}
// Driver code
public static void Main() {
string str = "PICTURE";
carveCross(str);
}
}
// This code is contributed by vt_m.
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to print the string
// in 'plus' pattern
// Function to make a cross
// in the matrix
function carveCross($str)
{
$n = strlen($str);
if ($n % 2 == 0)
{
/* As, it is not possible to make
the cross exactly in the middle of
the matrix with an even length string.*/
echo ("Not possible. Please enter ");
echo( "odd length string.\n");
}
else
{
// declaring a 2D array i.e a matrix
$arr = array();
$m = $n / 2;
/* Now, we will fill all the
elements of the array with 'X'*/
for ($i = 0; $i < $n; $i++)
{
for ($j = 0; $j < $n; $j++)
{
$arr[$i][$j] = 'X';
}
}
/* Now, we will place the characters
of the string in the matrix, such
that a cross is formed in it.*/
for ($i = 0; $i < $n; $i++)
{
/* here the characters of the
string will be added in the
middle column of our array.*/
$arr[$i][$m] = $str[$i];
}
for ($i = 0; $i < $n; $i++)
{
// here the characters of the
// string will be added in the
// middle row of our array.
$arr[$m][$i] = $str[$i];
}
/* Now finally, we will print
the array*/
for ($i = 0; $i < $n; $i++)
{
for ($j = 0; $j < $n; $j++)
{
echo ($arr[$i][$j] . " " );
}
echo ("\n");
}
}
}
// Driver Code
$str = "PICTURE";
carveCross($str);
// This code is contributed
// by Shivi_Aggarwal
?>
Output:
X X X P X X X
X X X I X X X
X X X C X X X
P I C T U R E
X X X U X X X
X X X R X X X
X X X E X X X
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