打印矩阵与其镜像之和
原文:https://www . geesforgeks . org/print-sum-matrix-and-it-mirror-image/
给你一个有序矩阵 N*N 。任务是通过将给定矩阵的镜像与矩阵本身相加来找到结果矩阵。 示例 :
Input : mat[][] = {{1, 2, 3},
{4, 5, 6},
{7, 8, 9}}
Output : 4 4 4
10 10 10
16 16 16
Explanation:
Resultant Matrix = {{1, 2, 3}, {{3, 2, 1},
{4, 5, 6}, + {6, 5, 4},
{7, 8, 9}} {9, 8, 7}}
Input : mat[][] = {{1, 2},
{3, 4}}
Output : 3 3
7 7
当找到矩阵的镜像时，每个元素的行将保持不变，但其列的值将重新排列。对于任何元素 A ij ，其在镜像中的新位置将是 A i(n-j) 。获得矩阵的镜像后，将其添加到原始矩阵并打印结果。 积分照顾:
- 矩阵的索引将从 0，0 开始，在 n-1，n-1 结束，因此任何元素 A ij 的位置将是 A i(n-1-j)。
- 打印结果时，请注意正确的输出格式
以下是上述方法的实现:
C++
// C++ program to find sum of matrix and
// its mirror image
#include <bits/stdc++.h>
#define N 4
using namespace std;
// Function to print the resultant matrix
void printSum(int mat[][N])
{
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
cout << setw(3) << mat[i][N - 1 - j] + mat[i][j] << " ";
}
cout << "\n";
}
}
// Driver Code
int main()
{
int mat[N][N] = { { 2, 4, 6, 8 },
{ 1, 3, 5, 7 },
{ 8, 6, 4, 2 },
{ 7, 5, 3, 1 } };
printSum(mat);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to find sum of
// matrix and its mirror image
import java.io.*;
class GFG
{
static int N = 4;
// Function to print the
// resultant matrix
static void printSum(int mat[][])
{
for (int i = 0; i < N; i++)
{
for (int j = 0; j < N; j++)
{
System.out.print((mat[i][N - 1 - j] +
mat[i][j]) + " ");
}
System.out.println();
}
}
// Driver Code
public static void main (String[] args)
{
int mat[][] = { { 2, 4, 6, 8 },
{ 1, 3, 5, 7 },
{ 8, 6, 4, 2 },
{ 7, 5, 3, 1 } };
printSum(mat);
}
}
// This code is contributed by anuj_67
Python 3
# Python 3 program to find sum of matrix
# and its mirror image
N = 4
# Function to print the resultant matrix
def printSum(mat):
for i in range(N):
for j in range(N):
print('{:>3}'.format(mat[i][N - 1 - j] +
mat[i][j]), end =" ")
print("\n", end = "")
# Driver Code
if __name__ == '__main__':
mat = [[2, 4, 6, 8],
[1, 3, 5, 7],
[8, 6, 4, 2],
[7, 5, 3, 1]]
printSum(mat)
# This code is contributed by
# Surendra_Gangwar
C
// C# program to find sum of
// matrix and its mirror image
using System;
class GFG
{
static int N = 4;
// Function to print the
// resultant matrix
static void printSum(int [,]mat)
{
for (int i = 0; i < N; i++)
{
for (int j = 0; j < N; j++)
{
Console.Write((mat[i, N - 1 - j] +
mat[i, j]) + " ");
}
Console.WriteLine();
}
}
// Driver Code
public static void Main ()
{
int [,]mat = { { 2, 4, 6, 8 },
{ 1, 3, 5, 7 },
{ 8, 6, 4, 2 },
{ 7, 5, 3, 1 } };
printSum(mat);
}
}
// This code is contributed by shs..
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to find sum of
// matrix and its mirror image
// Function to print the
// resultant matrix
function printSum($mat)
{
for ($i = 0; $i < 4; $i++)
{
for ($j = 0; $j < 4; $j++)
{
echo ($mat[$i][4 - 1 - $j] +
$mat[$i][$j]) . " " ;
}
echo "\n";
}
}
// Driver Code
$mat = array(array(2, 4, 6, 8 ),
array(1, 3, 5, 7),
array(8, 6, 4, 2),
array(7, 5, 3, 1));
printSum($mat);
// This code is contributed
// by Akanksha Rai
?>
java 描述语言
<script>
// Javascript program to find sum of matrix and
// its mirror image
var N = 4
// Function to print the resultant matrix
function printSum(mat)
{
for (var i = 0; i < N; i++) {
for (var j = 0; j < N; j++) {
document.write( (mat[i][N - 1 - j] + mat[i][j]) + " ");
}
document.write("<br>");
}
}
// Driver Code
var mat = [ [ 2, 4, 6, 8 ],
[ 1, 3, 5, 7 ],
[ 8, 6, 4, 2 ],
[ 7, 5, 3, 1 ] ];
printSum(mat);
</script>
Output:
10 10 10 10
8 8 8 8
10 10 10 10
8 8 8 8
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