不使用*、/和–
打印前 n 个自然数的正方形
原文:https://www . geesforgeks . org/print-squares-first-n-natural-numbers-不使用/
给定一个自然数“n”，不使用、/和-打印前 n 个自然数的平方。 例:*
Input: n = 5
Output: 0 1 4 9 16
Input: n = 6
Output: 0 1 4 9 16 25
强烈建议尽量减少浏览器，先自己试试这个。 方法一:思路是利用之前的平方值计算下一个平方。考虑以下 x 的平方和(x-1)之间的关系。我们知道(x-1)的平方是(x-1)2–2 * x+1。我们可以把 x 2 写成
x2 = (x-1)2 + 2*x - 1
x2 = (x-1)2 + x + (x - 1)
在编写迭代程序时，我们可以跟踪 x 的先前值，并将 x 的当前值和先前值加到 square 的当前值上。这样我们甚至不用“-”运算符。 以下是上述方法的实施:
C++
// C++ program to print squares of first 'n' natural numbers
// without using *, / and -
#include<iostream>
using namespace std;
void printSquares(int n)
{
// Initialize 'square' and previous value of 'x'
int square = 0, prev_x = 0;
// Calculate and print squares
for (int x = 0; x < n; x++)
{
// Update value of square using previous value
square = (square + x + prev_x);
// Print square and update prev for next iteration
cout << square << " ";
prev_x = x;
}
}
// Driver program to test above function
int main()
{
int n = 5;
printSquares(n);
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to print squares
// of first 'n' natural numbers
// without using *, / and
import java.io.*;
class GFG
{
static void printSquares(int n)
{
// Initialize 'square' and
// previous value of 'x'
int square = 0, prev_x = 0;
// Calculate and
// print squares
for (int x = 0; x < n; x++)
{
// Update value of square
// using previous value
square = (square + x + prev_x);
// Print square and update
// prev for next iteration
System.out.print( square + " ");
prev_x = x;
}
}
// Driver Code
public static void main (String[] args)
{
int n = 5;
printSquares(n);
}
}
// This code is contributed
// by akt_mit
Python 3
# Python 3 program to print squares of first
# 'n' natural numbers without using *, / and -
def printSquares(n):
# Initialize 'square' and previous
# value of 'x'
square = 0; prev_x = 0;
# Calculate and print squares
for x in range(0, n):
# Update value of square using
# previous value
square = (square + x + prev_x)
# Print square and update prev
# for next iteration
print(square, end = " ")
prev_x = x
# Driver Code
n = 5;
printSquares(n);
# This code is contributed
# by Akanksha Rai
C
// C# program to print squares
// of first 'n' natural numbers
// without using *, / and
using System;
public class GFG{
static void printSquares(int n)
{
// Initialize 'square' and
// previous value of 'x'
int square = 0, prev_x = 0;
// Calculate and
// print squares
for (int x = 0; x < n; x++)
{
// Update value of square
// using previous value
square = (square + x + prev_x);
// Print square and update
// prev for next iteration
Console.Write( square + " ");
prev_x = x;
}
}
// Driver Code
static public void Main (){
int n = 5;
printSquares(n);
}
}
// This code is contributed
// by ajit
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to print squares
// of first 'n' natural numbers
// without using *, / and -
function printSquares($n)
{
// Initialize 'square' and
// previous value of 'x'
$square = 0; $prev_x = 0;
// Calculate and
// print squares
for ($x = 0; $x < $n; $x++)
{
// Update value of square
// using previous value
$square = ($square + $x + $prev_x);
// Print square and update
// prev for next iteration
echo $square, " ";
$prev_x = $x;
}
}
// Driver Code
$n = 5;
printSquares($n);
// This code is contributed by ajit
?>
java 描述语言
<script>
// JavaScript program to print squares of first 'n' natural numbers
// without using *, / and -
function printSquares(n)
{
// Initialize 'square' and previous value of 'x'
let square = 0, prev_x = 0;
// Calculate and print squares
for (let x = 0; x < n; x++)
{
// Update value of square using previous value
square = (square + x + prev_x);
// Print square and update prev for next iteration
document.write(square + " ");
prev_x = x;
}
}
// Driver program to test above function
let n = 5;
printSquares(n);
// This code is contributed by Surbhi Tyagi
</script>
输出:
0 1 4 9 16
时间复杂度:0(n)
辅助空间:0(1)
方法二:前 n 个奇数之和是从 1 到 n 的自然数的平方，比如 1，1+3，1+3+5，1+3+5+7，1+3+5+7+9，…。 以下是基于上述概念的程序。感谢 Aadithya Umashanker 和 raviteja 提出这种方法。
C++
// C++ program to print squares of first 'n' natural numbers
// without using *, / and -
#include<iostream>
using namespace std;
void printSquares(int n)
{
// Initialize 'square' and first odd number
int square = 0, odd = 1;
// Calculate and print squares
for (int x = 0; x < n; x++)
{
// Print square
cout << square << " ";
// Update 'square' and 'odd'
square = square + odd;
odd = odd + 2;
}
}
// Driver program to test above function
int main()
{
int n = 5;
printSquares(n);
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to print
// squares of first 'n'
// natural numbers without
// using *, / and -
import java.io.*;
class GFG
{
static void printSquares(int n)
{
// Initialize 'square'
// and first odd number
int square = 0, odd = 1;
// Calculate and
// print squares
for (int x = 0; x < n; x++)
{
// Print square
System.out.print(square +
" " );
// Update 'square'
// and 'odd'
square = square + odd;
odd = odd + 2;
}
}
// Driver Code
public static void main (String[] args)
{
int n = 5;
printSquares(n);
}
}
// This code is contributed
// by ajit
Python 3
# Python3 program to print squares
# of first 'n' natural numbers
# without using *, / and -
def printSquares(n):
# Initialize 'square' and
# first odd number
square = 0
odd = 1
# Calculate and print squares
for x in range(0 , n):
# Print square
print(square, end= " ")
# Update 'square' and 'odd'
square = square + odd
odd = odd + 2
# Driver Code
n = 5;
printSquares(n)
# This code is contributed
# by Rajput-Ji
C
// C# program to print squares of first 'n'
// natural numbers without using *, / and -
using System;
class GFG
{
static void printSquares(int n)
{
// Initialize 'square'
// and first odd number
int square = 0, odd = 1;
// Calculate and
// print squares
for (int x = 0; x < n; x++)
{
// Print square
Console.Write(square + " " );
// Update 'square'
// and 'odd'
square = square + odd;
odd = odd + 2;
}
}
// Driver Code
public static void Main ()
{
int n = 5;
printSquares(n);
}
}
// This code is contributed
// by inder_verma..
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to print squares
// of first 'n' natural numbers
// without using *, / and -
function printSquares($n)
{
// Initialize 'square' and
// first odd number
$square = 0; $odd = 1;
// Calculate and print squares
for ($x = 0; $x < $n; $x++)
{
// Print square
echo $square , " ";
// Update 'square' and 'odd'
$square = $square + $odd;
$odd = $odd + 2;
}
}
// Driver Code
$n = 5;
printSquares($n);
// This code is contributed by m_kit
?>
java 描述语言
<script>
// Javascript program to print squares of first 'n' natural numbers
// without using *, / and -
function printSquares(n)
{
// Initialize 'square' and first odd number
let square = 0, odd = 1;
// Calculate and print squares
for (let x = 0; x < n; x++)
{
// Print square
document.write(square + " ");
// Update 'square' and 'odd'
square = square + odd;
odd = odd + 2;
}
}
// Driver program to test above function
let n = 5;
printSquares(n);
// This code is contributed by subham348.
</script>
输出:
0 1 4 9 16
时间复杂度:0(n)
辅助空间:0(1)
本文由沙钦供稿。如果你发现任何不正确的地方，请写评论，或者你想分享更多关于上面讨论的话题的信息
版权属于：月萌API www.moonapi.com，转载请注明出处
