打印字符串数组中最大长度的所有字符串
原文:https://www . geesforgeks . org/print-从字符串数组中打印最大长度的所有字符串/
给定一个字符串的数组arr[]，任务是打印给定数组中所有最大长度的字符串。
示例:
输入:arr[]= {“ABA”、“aa”、“ad”、“vcd”、“ABA”} 输出: aba vcd aba 解释: 给定数组中所有字符串的最大长度为 3。 数组中长度等于 3 的字符串为“aba”、“vcd”、“aba”。
输入:arr[]= {“abb”、“abcd”、“guw”、“v”} 输出: abcd 解释: 给定数组中所有字符串的最大长度为 4。 数组中长度等于 4 的字符串是“abcd”。
方法:按照以下步骤解决问题:
- 遍历给定的字符串数组。计算数组中所有字符串的最大长度，并将其存储在一个变量中，比如 len 。
- 现在，再次遍历字符串数组，打印数组中长度等于 len 的字符串。
下面是上述方法的实现:
C++
// C++ program to implement
// the above approach
#include <bits/stdc++.h>
using namespace std;
// Function to find the length
// of the longest string from
// the given array of strings
int maxLength(vector<string> arr)
{
int len = INT_MIN;
int N = arr.size();
// Traverse the array
for (int i = 0; i < N; i++) {
// Stores the length
// of current string
int l = arr[i].size();
// Update maximum length
if (len < l) {
len = l;
}
}
// Return the maximum length
return len;
}
// Function to print the
// longest strings from the array
void maxStrings(vector<string> arr, int len)
{
int N = arr.size();
vector<string> ans;
// Find the strings having length
// equals to len
for (int i = 0; i < N; i++) {
if (len == arr[i].size()) {
ans.push_back(arr[i]);
}
}
// Print the resultant
// vector of strings
for (int i = 0; i < ans.size(); i++) {
cout << ans[i] << " ";
}
}
// Function to print all the
// longest strings from the array
void printStrings(vector<string>& arr)
{
// Find the length of longest string
int max = maxLength(arr);
// Find and print all the strings
// having length equals to max
maxStrings(arr, max);
}
// Driver Code
int main()
{
vector<string> arr
= { "aba", "aa", "ad", "vcd", "aba" };
printStrings(arr);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to implement
// the above approach
import java.util.*;
class GFG{
// Function to find the length
// of the longest String from
// the given array of Strings
static int maxLength(String []arr)
{
int len = Integer.MIN_VALUE;
int N = arr.length;
// Traverse the array
for(int i = 0; i < N; i++)
{
// Stores the length
// of current String
int l = arr[i].length();
// Update maximum length
if (len < l)
{
len = l;
}
}
// Return the maximum length
return len;
}
// Function to print the
// longest Strings from the array
static void maxStrings(String []arr, int len)
{
int N = arr.length;
Vector<String> ans = new Vector<String>();
// Find the Strings having length
// equals to len
for(int i = 0; i < N; i++)
{
if (len == arr[i].length())
{
ans.add(arr[i]);
}
}
// Print the resultant
// vector of Strings
for(int i = 0; i < ans.size(); i++)
{
System.out.print(ans.get(i) + " ");
}
}
// Function to print all the
// longest Strings from the array
static void printStrings(String [] arr)
{
// Find the length of longest String
int max = maxLength(arr);
// Find and print all the Strings
// having length equals to max
maxStrings(arr, max);
}
// Driver Code
public static void main(String[] args)
{
String []arr = { "aba", "aa", "ad",
"vcd", "aba" };
printStrings(arr);
}
}
// This code is contributed by Amit Katiyar
Python 3
# Python3 program to implement
# the above approach
import sys
# Function to find the length
# of the longest string from
# the given array of strings
def maxLength(arr):
lenn = -sys.maxsize - 1
N = len(arr)
# Traverse the array
for i in range(N):
# Stores the length
# of current string
l = len(arr[i])
# Update maximum length
if (lenn < l):
lenn = l
# Return the maximum length
return lenn
# Function to print the
# longest strings from the array
def maxStrings(arr, lenn):
N = len(arr)
ans = []
# Find the strings having length
# equals to lenn
for i in range(N):
if (lenn == len(arr[i])):
ans.append(arr[i])
# Print the resultant
# vector of strings
for i in range(len(ans)):
print(ans[i], end = " ")
# Function to print all the
# longest strings from the array
def printStrings(arr):
# Find the length of longest string
max = maxLength(arr)
# Find and print all the strings
# having length equals to max
maxStrings(arr, max)
# Driver Code
if __name__ == '__main__':
arr = [ "aba", "aa", "ad",
"vcd", "aba" ]
printStrings(arr)
# This code is contributed by mohit kumar 29
C
// C# program to implement
// the above approach
using System;
using System.Collections.Generic;
class GFG{
// Function to find the length
// of the longest String from
// the given array of Strings
static int maxLength(String []arr)
{
int len = int.MinValue;
int N = arr.Length;
// Traverse the array
for(int i = 0; i < N; i++)
{
// Stores the length
// of current String
int l = arr[i].Length;
// Update maximum length
if (len < l)
{
len = l;
}
}
// Return the maximum length
return len;
}
// Function to print the
// longest Strings from the array
static void maxStrings(String []arr,
int len)
{
int N = arr.Length;
List<String> ans = new List<String>();
// Find the Strings having length
// equals to len
for(int i = 0; i < N; i++)
{
if (len == arr[i].Length)
{
ans.Add(arr[i]);
}
}
// Print the resultant
// vector of Strings
for(int i = 0; i < ans.Count; i++)
{
Console.Write(ans[i] + " ");
}
}
// Function to print all the
// longest Strings from the array
static void printStrings(String [] arr)
{
// Find the length of longest String
int max = maxLength(arr);
// Find and print all the Strings
// having length equals to max
maxStrings(arr, max);
}
// Driver Code
public static void Main(String[] args)
{
String []arr = {"aba", "aa", "ad",
"vcd", "aba"};
printStrings(arr);
}
}
// This code is contributed by Rajput-Ji
java 描述语言
<script>
// Javascript program to implement
// the above approach
// Function to find the length
// of the longest String from
// the given array of Strings
function maxLength(arr)
{
let len = Number.MIN_VALUE;
let N = arr.length;
// Traverse the array
for(let i = 0; i < N; i++)
{
// Stores the length
// of current String
let l = arr[i].length;
// Update maximum length
if (len < l)
{
len = l;
}
}
// Return the maximum length
return len;
}
// Function to print the
// longest Strings from the array
function maxStrings(arr,len)
{
let N = arr.length;
let ans = [];
// Find the Strings having length
// equals to len
for(let i = 0; i < N; i++)
{
if (len == arr[i].length)
{
ans.push(arr[i]);
}
}
// Print the resultant
// vector of Strings
for(let i = 0; i < ans.length; i++)
{
document.write(ans[i] + " ");
}
}
// Function to print all the
// longest Strings from the array
function printStrings(arr)
{
// Find the length of longest String
let max = maxLength(arr);
// Find and print all the Strings
// having length equals to max
maxStrings(arr, max);
}
// Driver Code
let arr=["aba", "aa", "ad",
"vcd", "aba" ];
printStrings(arr);
// This code is contributed by unknown2108
</script>
Output:
aba vcd aba
时间复杂度:O(N) T5辅助空间:** O(N)
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